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I'm a complete newbie to programming and php, my code's throwing back an error saying there's an unexpected end to the file and I can't for the life of me see what's missing or there that shouldn't be. Can anyone spot it?

<html>
<head>
<title><?php echo $firstname; ?> <?php echo $lastname; ?>'s Profile</title>
</head>
<body>
<?php

if (isset($_GET['username'])){
 	$username = $_GET['username'];
    mysql_connect("localhost","root", "") or die ("Could not connect to the server");
    mysql_select_db("users") or die ("That database could not be found.");
	$userquery = mysql_query("SELECT * FROM users WHERE username='$username'") or die ("The query could not be completed, please try again later.");
	if(mysql_num_rows($userquery) !=1){
		die ("That user could not be found.");
	}
	while($row = mysql_fetch_array($userquery, MYSQL_ASSOC)) {
		$firstname = $row['firstname'];
		$lastname = $row['lastname'];
		$email = $row['email'];
		$dbusername = $row['dbusername'];
		$access = $row['access'];
		}
		if($username != $dbusername){
			die ("There has been a fatal error, please try again.");		
		}
	
		if($access == 1) {
			$access = "Level 1 User";
		} else 
			if($access == 2) {
				$access = "Level 2 User";
			}	else 
					if($access == 3) {
						$access = "Level 3 User";
					} else 
						if($access == 4) {
							$access = "Administrator.";
						} else die ("This user has an access level beyond the realms of possibility. Beware.");
	
					

?>

<h2><?php echo $firstname; ?> <?php echo $lastname; ?>'s Profile</h2><br />
<table>
	<tr><td>Firstname:</td><td><?php echo $firstname; ?></td></tr>
    <tr><td>Lastname:</td><td><?php echo $lastname; ?></td></tr>
    <tr><td>email:</td><td><?php echo $email; ?></td></tr>
	<tr><td>dbusername:</td><td><?php echo $dbusername; ?></td></tr>
	<tr><td>access:</td><td><?php echo $access; ?></td></tr>
</table>
</body>
</html>

4

1 回答 1

0

是需要用 } 关闭的主要 if 代码块

<html>
<head>
<title><?php echo $firstname; ?> <?php echo $lastname; ?>'s Profile</title>
</head>
<body>
<?php

if (isset($_GET['username'])){
 	$username = $_GET['username'];
    mysql_connect("localhost","root", "") or die ("Could not connect to the server");
    mysql_select_db("users") or die ("That database could not be found.");
	$userquery = mysql_query("SELECT * FROM users WHERE username='$username'") or die ("The query could not be completed, please try again later.");
	if(mysql_num_rows($userquery) !=1){
		die ("That user could not be found.");
	}
	while($row = mysql_fetch_array($userquery, MYSQL_ASSOC)) {
		$firstname = $row['firstname'];
		$lastname = $row['lastname'];
		$email = $row['email'];
		$dbusername = $row['dbusername'];
		$access = $row['access'];
		}
		if($username != $dbusername){
			die ("There has been a fatal error, please try again.");		
		}
	
		if($access == 1) {
			$access = "Level 1 User";
		} else 
			if($access == 2) {
				$access = "Level 2 User";
			}	else 
					if($access == 3) {
						$access = "Level 3 User";
					} else 
						if($access == 4) {
							$access = "Administrator.";
						} else die ("This user has an access level beyond the realms of possibility. Beware.");
}//THIS IS WHAT IS MISSING
					

?>

<h2><?php echo $firstname; ?> <?php echo $lastname; ?>'s Profile</h2><br />
<table>
	<tr><td>Firstname:</td><td><?php echo $firstname; ?></td></tr>
    <tr><td>Lastname:</td><td><?php echo $lastname; ?></td></tr>
    <tr><td>email:</td><td><?php echo $email; ?></td></tr>
	<tr><td>dbusername:</td><td><?php echo $dbusername; ?></td></tr>
	<tr><td>access:</td><td><?php echo $access; ?></td></tr>
</table>
</body>
</html>

于 2014-10-19T06:02:06.540 回答