11

我正在使用 Swift 中的 UITableView 和 UISearchBar 开发一个新应用程序，它已经运行良好。但由于最终项目必须有一个完整的自定义搜索栏，我不得不将 UITextField 作为输入 Outlet，因为可以自定义。

问题是我无法弄清楚如何编码，以便 UITextField 的行为类似于 UISearchBar。不知道如何过滤 UITextField 输入并使字符串可用于 UISearchBarDelegate 方法。

所以有人可以帮我解决这个问题吗？

编辑：我按照丹尼尔的帮助想出了这段代码，但它返回“nil”，不工作。

class ViewController: UIViewController, UITableViewDataSource, UITableViewDelegate, UITextFieldDelegate {

@IBOutlet weak var txtSearchBar: UITextField!
var searchTxt = ""
let prods = ["água", "terra", "ar", "fogo"]
var searchResults:[String] = []

override func viewDidLoad() {
    super.viewDidLoad()
    // Do any additional setup after loading the view, typically from a nib.
    
    txtSearchBar.delegate = self
}


func textFieldDidEndEditing(textField: UITextField) {
    searchTxt = textField.text
    println(searchTxt)
    searchResults = prods.filter({(produtos:String) -> Bool in
        
        let nameMatch = produtos.rangeOfString(self.searchTxt, options: NSStringCompareOptions.CaseInsensitiveSearch)
        
        println(nameMatch)
        return nameMatch != nil})
}

我的输入是字母“ar”，但它返回“nil”，而它不应该返回，因为数组的对象之一是“ar”。

4

4 回答 4

12

创建 uitextfield 对象：

@IBOutlet var SearchTxt: UITextField!
var search:String=""

@IBOutlet var ListTable: UITableView!
var AllData:Array<Dictionary<String,String>> = []
var SearchData:Array<Dictionary<String,String>> = []

查看didload：

override func viewDidLoad()
{
    super.viewDidLoad()

    AllData = [["pic":"list0.jpg", "name":"Angel Mark", "msg":"Hi there, I would like read your...", "time":"just now", "unread":"12"],
               ["pic":"list1.jpg", "name":"John Doe", "msg":"I would prefer reading on night...", "time":"56 second ago", "unread":"2"],
               ["pic":"list2.jpg", "name":"Krishta Hide", "msg":"Okey Great..!", "time":"2m ago", "unread":"0"],
               ["pic":"list3.jpg", "name":"Keithy Pamela", "msg":"I am waiting there", "time":"5h ago", "unread":"0"]
               ]

    SearchData=AllData
}

在文本字段委托方法中搜索：

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool
{
    if string.isEmpty
    {
        search = String(search.characters.dropLast())
    }
    else
    {
        search=textField.text!+string
    }

    print(search)
    let predicate=NSPredicate(format: "SELF.name CONTAINS[cd] %@", search)
    let arr=(AllData as NSArray).filtered(using: predicate)

    if arr.count > 0
    {
        SearchData.removeAll(keepingCapacity: true)
        SearchData=arr as! Array<Dictionary<String,String>>
    }
    else
    {
        SearchData=AllData
    }
    ListTable.reloadData()
    return true
}

搜索数据在 tableview 中显示：

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int
{
    return SearchData.count
}

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell
{
    let cell = tableView.dequeueReusableCell(withIdentifier: "ListCell") as! ListCell

    var Data:Dictionary<String,String> = SearchData[indexPath.row]

    cell.Pic.image=UIImage(named: Data["pic"]!)
    cell.Name.text = Data["name"]
    cell.Msg.text = Data["msg"]
    cell.Time.text = Data["time"]

    cell.selectionStyle = .none
    return cell
}
于 2016-11-10T05:28:58.473 回答
3

您的主要问题似乎是询问如何实现一个像 UISearchBar 一样工作的类。那将是一项艰巨的任务！

但是，在您的笔记中，您只是询问如何对被点击的搜索按钮做出反应。

将 IBAction 和第二个数组添加到您的视图控制器。将第二个数组称为“foundItems”。将 IBAction 连接到搜索按钮。调用操作时，从文本字段中读取文本并根据该文本过滤项目。将符合过滤器的项目放在 foundItems 数组中，然后在表视图上调用 reloadData()。

在您的表视图数据源方法中，检查 foundItems 是否不为零。如果不是，则显示它们而不是您的主要项目数组。

您还需要某种取消按钮。在该按钮的操作中，将 foundItems 数组清零并在表视图上调用 reloadData()。

于 2014-10-19T01:56:28.270 回答
3

Xcode 9.2 / Swift 4 -- 工作代码

 @IBOutlet var tfSearchWorker: UITextField!
 @IBOutlet var tblView: UITableView!

 var AllData :Array<Dictionary<String,String>> = []
 var SearchedData:Array<Dictionary<String,String>> = []

@ViewDidLoad

 AllData = [["pic":"list0.jpg", "name":"Angel Mark", "msg":"Hi there, I would like read your...", "time":"just now", "unread":"12"],
           ["pic":"list1.jpg", "name":"John Doe", "msg":"I would prefer reading on night...", "time":"56 second ago", "unread":"2"],
           ["pic":"list2.jpg", "name":"Krishta Hide", "msg":"Okey Great..!", "time":"2m ago", "unread":"0"],
           ["pic":"list3.jpg", "name":"Keithy Pamela", "msg":"I am waiting there", "time":"5h ago", "unread":"0"]
           ]

self.SearchedData = self.AllData
self.tfSearchWorker.addTarget(self, action: #selector(searchWorkersAsPerText(_ :)), for: .editingChanged)

@功能

@objc func searchWorkersAsPerText(_ textfield:UITextField) {
    self.SearchedData.removeAll()
    if textfield.text?.count != 0 {
        for dicData in self.AllData {
            let isMachingWorker : NSString = (dicData.name!) as NSString
            let range = isMachingWorker.lowercased.range(of: textfield.text!, options: NSString.CompareOptions.caseInsensitive, range: nil,   locale: nil)
            if range != nil {
                SearchedData.append(dicData)
            }
        }
    } else {
        self.SearchedData = self.AllData
    }
    self.tblView.reloadData()
}

@UITableView

 func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
     return self.SearchedData.count
}

 func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell
{
     let cell = tableView.dequeueReusableCell(withIdentifier: "ListCell") as! ListCell

     var Data:Dictionary<String,String> = SearchedData[indexPath.row]

     cell.Pic.image=UIImage(named: Data["pic"]!)
     cell.Name.text = Data["name"]
     cell.Msg.text = Data["msg"]
     cell.Time.text = Data["time"]

     cell.selectionStyle = .none
     return cell
}
于 2018-05-09T11:55:37.433 回答
1

在@Daniel T 的帮助下，我设法用以下代码解决了这个问题：

func textFieldShouldReturn(textField: UITextField) -> Bool {
    isFiltered = true
    searchResults = prods.filter({(coisas:String) -> Bool in
        let stringMatch = coisas.rangeOfString(textField.text)
        return stringMatch != nil

    })
    println(searchResults.description)
    textField.resignFirstResponder()
    table.reloadData()
    return true
}

谢谢@Daniel T。

于 2014-10-19T04:21:26.283 回答