1

我想在客户端更改一些 MVC Ajax 表单参数，例如InsertionMode或通过 javascript。 我该怎么做？LoadingElementId

MVC ajax 表单示例：

@using (Ajax.BeginRouteForm("DevicesByObjectName", new AjaxOptions
{
    InsertionMode = InsertionMode.InsertBefore,
    UpdateTargetId = "Devices",
    LoadingElementId = "LoaderContents",
    OnSuccess = "MoreDevicesOnSuccess",
    OnFailure = "MoreDevicesOnFailure",
    OnBegin = "MoreDevicesOnBegin",
    OnComplete = "MoreDevicesOnComplete",
}))
{
    <div>
        @Html.AntiForgeryToken()
        <input type="hidden" value="@Model.Object.Id" id="ObjectId" name="ObjectId" />
        <input type="hidden" value="2" id="PageNumber" name="PageNumber" />
        <input type="hidden" value="" id="Filtering" name="Filtering" />

        <div class="center-block" style="max-width: 360px;">
            <input type="submit" value=" more" class="btn btn-primary btn-lg btn-block center-block" />
        </div>
        <div id="LoaderContents" class="ajax-loader center-block hidden"></div>
    </div>
}
4

1 回答 1

2

BeginRouteForm生成一个<form>带有一系列data-xxx属性的标签AjaxOptions，例如

<form ... data-ajax-loading="#LoaderContents" data-ajax-mode="before" ...>

您可以使用 jquery.data()或.attr()方法获取和设置这些。所以对于你的助手生成的表格

console.log($('form').data('ajax-mode')); // returns before
$('form').data('ajax-mode', 'after'); // change the insertion mode
console.log($('form').data('ajax-mode')); // returns after
于 2014-10-25T06:04:40.127 回答