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我正在尝试在 Jongo 驱动程序函数上使用 MongoDB shell 函数（如 Date()）来为我的 fiedd 生成一个值。代码如下：

collection.insert( "{ date: Date() }" );

但这似乎不起作用，有什么建议吗？

这些是错误行

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException
at java.lang.System.arraycopy(Native Method)
at org.bson.io.PoolOutputBuffer.write(PoolOutputBuffer.java:89)
at org.bson.LazyBSONObject.pipe(LazyBSONObject.java:474)
at org.jongo.bson.BsonDBEncoder.writeObject(BsonDBEncoder.java:39)
at com.mongodb.BSONBinaryWriter.encodeDocument(BSONBinaryWriter.java:339)
at com.mongodb.InsertCommandMessage.writeTheWrites(InsertCommandMessage.java:45)
at com.mongodb.InsertCommandMessage.writeTheWrites(InsertCommandMessage.java:23)
at com.mongodb.BaseWriteCommandMessage.encodeMessageBody(BaseWriteCommandMessage.java:69)
at com.mongodb.BaseWriteCommandMessage.encodeMessageBody(BaseWriteCommandMessage.java:23)
at com.mongodb.RequestMessage.encode(RequestMessage.java:66)
at com.mongodb.BaseWriteCommandMessage.encode(BaseWriteCommandMessage.java:53)
at com.mongodb.DBCollectionImpl.sendWriteCommandMessage(DBCollectionImpl.java:473)
at com.mongodb.DBCollectionImpl.writeWithCommandProtocol(DBCollectionImpl.java:427)
at com.mongodb.DBCollectionImpl.insertWithCommandProtocol(DBCollectionImpl.java:387)
at com.mongodb.DBCollectionImpl.insert(DBCollectionImpl.java:186)
at com.mongodb.DBCollectionImpl.insert(DBCollectionImpl.java:165)
at com.mongodb.DBCollection.insert(DBCollection.java:161)
at com.mongodb.DBCollection.insert(DBCollection.java:107)
at com.mongodb.DBCollection.save(DBCollection.java:966)
at org.jongo.Insert.save(Insert.java:49)
at org.jongo.MongoCollection.save(MongoCollection.java:128)
at learningjongo.DAO.setUp(DAO.java:42)
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1 回答 1

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我建议你这样做

collection.insert("{ date: # }", new java.util.Date());

这相当于做{ date: ISODate() }or { date: new Date() }。

Date()按照您在问题中的建议使用会产生一个字符串，因此要模仿这种行为，您只需执行类似的操作

collection.insert("{ date: # }", new java.util.Date().toString());

但如果您有选择，我建议您将其存储为适当的日期，而不是字符串。

于 2014-10-08T19:37:44.323 回答