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大家晚上好,

谁能告诉我如何从 MTF 指标获得总结果,例如 MACD:

M1= 买, M5= 卖, M15= 卖, M30= 买, H1= 买, H4= 买, D1= 买,

总结果 = 5 买 & 2 卖

如何将其实现到MQL4代码中?感谢您的所有回答。

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1 回答 1

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要考虑的示例代码:

start() {
    //--------------------------------------------
    // Get the MACD values for all time-frames
    //--------------------------------------------
    double vaiMACD[7];
    vaiMACD[0] = iMACD( Symbol(), PERIOD_M1, 12, 26, 9, PRICE_CLOSE, MODE_SIGNAL, 0);
    vaiMACD[1] = iMACD( Symbol(), PERIOD_M5, 12, 26, 9, PRICE_CLOSE, MODE_SIGNAL, 0);
    vaiMACD[2] = iMACD( Symbol(), PERIOD_M15, 12, 26, 9, PRICE_CLOSE, MODE_SIGNAL, 0);
    vaiMACD[3] = iMACD( Symbol(), PERIOD_M30, 12, 26, 9, PRICE_CLOSE, MODE_SIGNAL, 0);
    vaiMACD[4] = iMACD( Symbol(), PERIOD_H1, 12, 26, 9, PRICE_CLOSE, MODE_SIGNAL, 0);
    vaiMACD[5] = iMACD( Symbol(), PERIOD_H4, 12, 26, 9, PRICE_CLOSE, MODE_SIGNAL, 0);
    vaiMACD[6] = iMACD( Symbol(), PERIOD_D1, 12, 26, 9, PRICE_CLOSE, MODE_SIGNAL, 0);
    //--------------------------------------------

    //--------------------------------------------
    // CALC: Total Buys/Sells
    //--------------------------------------------
    int viMACDSignalBuyCount  = 0;
    int viMACDSignalSellCount = 0;
    for( int viElement=0; viElement<ArrayRange(vaiMACD, 0); viElement++) {
        //-----------------------------------------------------------
        // Here, you need to define your own rules on what is considered as Buy/Sell signal.
        // My example here is a simple: >0 is Buy. <0 is Sell.
        //-----------------------------------------------------------
        if( vaiMACD[viElement]>0 )    viMACDSignalBuyCount  += 1;
        if( vaiMACD[viElement]<0 )    viMACDSignalSellCount  += 1;
    }
    //--------------------------------------------

    //--------------------------------------------
    // Display Outcome
    //--------------------------------------------
    Comment( "Total MACD Signals:"
        + " " + viMACDSignalBuyCount + " (Buy)"
        + ", " + viMACDSignalSellCount + " (Sell)"
    );
}
于 2015-03-05T00:20:58.040 回答