jquery - jQuery: Selecting all elements where attribute is greater than a value

Question

I know that to filter an element with an atttribute called attrName which has value attrValue I do:

filter("[attrName='attrValue']")

but looking at the docs http://api.jquery.com/category/selectors/ I can't see an option to select all elements s.t. attrName>attrValue

Will this work

   filter("[attrName>'attrValue']")

Answer 1

You can do this using the function overload of .filter(), like this:

.filter(function() {
  return $(this).attr("attrName") > "someValue";
})

Answer 2

小心，如果你在玩整数，请确保你使用的是parseInt().

$("selector").filter(function() {
    return parseInt($(this).attr("my-attr")) > 123;
});

Answer 3

The solution is jQuery.filter():

$("selector").filter(function() {
    return  $(this).attr("my-attr") > 123;
});

Answer 4

对于 ES6 箭头函数

$("selector").filter((index, el) => {
    return parseInt($(el).attr("attrName")) > 123;
});