我尝试使用所有常规操作(合并、删除最小等)实现“配对堆”,然后我被要求编写一个函数,该函数将使用我新构建的堆实现对列表进行排序。不幸的是,似乎出了点问题……
以下是相关代码:
(define (heap-merge h1 h2)
(cond ((heap-empty? h1) h2)
((heap-empty? h2) h1)
(else (let ((min1 (heap-get-min h1))
(min2 (heap-get-min h2)))
(if ((heap-get-less h1) min1 min2)
(make-pairing-heap (heap-get-less h1) min1 (cons h2 (heap-get-subheaps h1)))
(make-pairing-heap (heap-get-less h1) min2 (cons h1 (heap-get-subheaps h2))))))))
(define (heap-insert element h)
(heap-merge (make-pairing-heap (heap-get-less h) element '())
h))
(define (heap-delete-min h)
(define (merge-in-pairs less? subheaps)
(cond
((null? subheaps) (make-heap less?))
((null? (cdr subheaps)) (car subheaps))
(else (heap-merge (heap-merge (car subheaps) (cadr subheaps))
(merge-in-pairs less? (cddr subheaps))))))
(if (heap-empty? h) (error "expected pairing-heap for first argument, got an empty heap ")
(merge-in-pairs (heap-get-less h) (heap-get-subheaps h))))
(define (heapsort l less?)
(let aux ((h (accumulate heap-insert (make-heap less?) l)))
(if (not (heap-empty? h))
(cons (heap-get-min h)
(aux (heap-delete-min h))))))
这些是一些可以帮助您理解代码的选择器:
(define (make-pairing-heap less? min subheaps)
(cons less? (cons min subheaps)))
(define (make-heap less?)
(cons less? '()))
(define (heap-get-less h)
(car h))
(define (heap-empty? h)
(if (null? (cdr h)) #t #f))
现在让我们来解决问题:当我运行“heapsort”时,它会返回带有“void”的排序列表,如您所见:
> (heapsort (list 1 2 3) <)
(1 2 3 . #<void>)
..我该如何解决?
问候, Superguay