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我正在对我的原始网络分析数据进行一些分析，并试图在我的网站上找到导致购买的常见到达路径。我已将所有数据迁移到下面的一个整洁的表/脚本中：

  1. [ORDER_ID]：非唯一 VARCHAR（A1000、A1001 等）
  2. [VISIT_IN_PATH]：数字（1、2、3、4、5 等）
  3. [VISIT_REMAINING]：数字（1,2,3,4,5 等）
  4. [频道]：VARCHAR（直接/电子邮件/显示/付费搜索/免费搜索）

我希望得到的是路径的计数，因此例如仅使用 ORDER_ID ABC123 我可能会得到以下信息：

COUNT/VISIT_IN_PATH_1/VISIT_IN_PATH_2/VISIT_IN_PATH_3/VISIT_IN_PATH_4/VISIT_IN_PATH_5 1/免费搜索/免费搜索/直接/免费搜索/直接

我对 SQL 很陌生，我的第一个想法是某种支点，但我每次接近这个问题时都会遇到必须定义每种可能性的墙。

当然有更好更简单的方法吗？

CREATE TABLE [dbo].[DummyPaths](
                                    [ORDER_ID] [varchar](64) NULL,
                                    [VISIT_IN_PATH] [bigint] NULL,
                                    [VISIT_REMAINING] [bigint] NULL,
                                    [MARKETING_CHANNEL] [varchar](256) NULL
                                )
GO

INSERT INTO DummyPaths (ORDER_ID,VISIT_IN_PATH,VISIT_REMAINING,MARKETING_CHANNEL)
VALUES      ('ABC123','1','5','FREE SEARCH'),
            ('ABC123','2','4','FREE SEARCH'),
            ('ABC123','3','3','DIRECT'),
            ('ABC123','4','2','FREE SEARCH'),
            ('ABC123','5','1','DIRECT'),
            ('ABC124','1','5','OTHER REFERRAL'),
            ('ABC124','2','4','OTHER REFERRAL'),
            ('ABC124','3','3','OTHER REFERRAL'),
            ('ABC124','4','2','OTHER REFERRAL'),
            ('ABC124','5','1','OTHER REFERRAL'),
            ('ABC125','1','5','DIRECT'),
            ('ABC125','2','4','AFFILIATE'),
            ('ABC125','3','3','AFFILIATE'),
            ('ABC125','4','2','AFFILIATE'),
            ('ABC125','5','1','AFFILIATE'),
            ('ABC126','1','5','EMAIL'),
            ('ABC126','2','4','EMAIL'),
            ('ABC126','3','3','DIRECT'),
            ('ABC126','4','2','DIRECT'),
            ('ABC126','5','1','DIRECT'),
            ('ABC127','1','5','FREE SEARCH'),
            ('ABC127','2','4','DIRECT'),
            ('ABC127','3','3','DIRECT'),
            ('ABC127','4','2','FREE SEARCH'),
            ('ABC127','5','1','DIRECT'),
            ('ABC128','1','5','DIRECT'),
            ('ABC128','2','4','EMAIL'),
            ('ABC128','3','3','EMAIL'),
            ('ABC128','4','2','EMAIL'),
            ('ABC128','5','1','DIRECT'),
            ('ABC129','1','5','FREE SEARCH'),
            ('ABC129','2','4','FREE SEARCH'),
            ('ABC129','3','3','FREE SEARCH'),
            ('ABC129','4','2','FREE SEARCH'),
            ('ABC129','5','1','DIRECT')

如果有任何帮助，我将不胜感激。

谢谢

4

1 回答 1

0

我一直在玩这个，发现以下工作：

with        dataset
as
(
select  ORDER_ID
        ,[1] as 'VISIT1'
        ,[2] as 'VISIT2'
        ,[3] as 'VISIT3'
        ,[4] as 'VISIT4'
        ,[5] as 'VISIT5'                
from 
(
  select order_id, visit_in_path, MARKETING_CHANNEL
  from dummypaths
) x
pivot
(
  min(MARKETING_CHANNEL)
  for visit_in_path in ([1], [2], [3], [4], [5])
) p
) 


select      x.VISIT1
            ,x.VISIT2
            ,x.VISIT3
            ,x.VISIT4
            ,x.VISIT5
            ,MAX(dupes) as 'count'
from
(
select      
            VISIT1
            ,VISIT2
            ,VISIT3
            ,VISIT4
            ,VISIT5
            ,ROW_NUMBER() over 
                            (partition by    VISIT1
                                            ,VISIT2
                                            ,VISIT3
                                            ,VISIT4
                                            ,VISIT5
                            order by        VISIT1 asc
                            ) as 'dupes'
from dataset
) x
group by    x.VISIT1
            ,x.VISIT2
            ,x.VISIT3
            ,x.VISIT4
            ,x.VISIT5
于 2014-09-24T12:12:21.337 回答