-2

我收到此错误：不兼容的类型
k0= (i==0 * 2);
......^

导入 java.util.Scanner；公共课 pers5 {

public static void main(String[] args) {

int k0,k1,k2,k3,k4,k5,k6,k7,k8,k9;
int produkt;

System.out.print("ange ett personnummer: ");
String indata = new Scanner(System.in).nextLine();
for (int i=0; i<10; i++){
    int nummer=indata.charAt(i) -48;
        System.out.print(indata.charAt(i)+ " ");
        System.out.println(indata.charAt(i));
//this code has lots of stuff between these two but its irrelevant.
k0= (i==0 * 2);
k1= (i==1 * 1);
k2= (i==2 * 2);
k3= (i==3 * 1);
k4= (i==4 * 2);
k5= (i==5 * 1);
k6= (i==6 * 2);
k7= (i==7 * 1);
k8= (i==8 * 2);
k9= (i==9 * 1);
produkt= k0+k1+k2+k3+k4+k5+k6+k7+k8+k9;
4

2 回答 2

1

i==0并且随后的调用返回一个布尔值，因此它不能分配给 k0 因为它是类型int

于 2014-09-24T10:02:09.440 回答
0

你错过了重点

k0 = (i == 0 * 2); // i == 0 * 2 resulting a boolean

所以k0必须是一个boolean。您可以使用boolean而不是int

于 2014-09-24T10:02:17.760 回答