0

大家好,我正在尝试编写一个使用控制结构将数字转换为单词的简单程序,但程序变得太长了。有没有更简单的写法?例如,如果用户输入 123,则输出应该是一二三。我没有完成它,但这里有一个示例:

import java.util.Scanner;
public class Number10 {

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    String num;

    System.out.print("Enter a number and i'll convert it to words: ");
    num = input.nextLine();

    if((num.length()) == 1)
    {
        switch(num)
        {
        case "0":
        {
            System.out.print("Zero");
            break;
        }
        case "1":
        {
            System.out.print("One");
            break;
        }
        case "2":
        {
            System.out.print("Two");
            break;
        }
        case "3":
        {
            System.out.print("Three");
            break;
        }
        case "4":
        {
            System.out.print("Four");
            break;
        }
        case "5":
        {
            System.out.print("Five");
            break;
        }
        case "6":
        {
            System.out.print("Six");
            break;
        }
        case "7":
        {
            System.out.print("Seven");
            break;
        }
        case "8":
        {
            System.out.print("Eight");
            break;
        }
        case "9":
        {
            System.out.print("Nine");
            break;
        }
        default:
        {
            System.out.print("Please enter a number");
            break;
        }
        }
 }
    else if((num.length()) == 2)
    {
        switch(num)
        {
        case "11":
        {
            System.out.print("One One");
            break;
        }
        case "12":
        {
            System.out.print("One Two");
            break;
        }
        case "13":
        {
            System.out.print("One Three");
            break;
        }
        case "14":
        {
            System.out.print("One Four");
            break;
        }
        case "15":
        {
            System.out.print("One Five");
            break;
        }
        case "16":
        {
            System.out.print("One Six");
            break;
        }
        case "17":
        {
            System.out.print("One Seven");
            break;
        }
        case "18":
        {
            System.out.print("One Eight");
            break;
        }
        case "19":
        {
            System.out.print("One Nine");
            break;
        }
        case "20":
        {
            System.out.print("Two Zero");
            break;
        }
        case "21":
        {
            System.out.print("Two One");
            break;
        }
        case "22":
        {
            System.out.print("Two Two");
            break;
        }
        case "23":
        {
            System.out.print("Two Three");
            break;
        }
        case "24":
        {
            System.out.print("Two Four");
            break;
        }

        default:
        {
            System.out.print("Please enter a number");
            break;
        }
        }
    }

    else
    {
        System.out.print("Invalid number");
    }

}

}

请帮帮我。谢谢。

4

3 回答 3

1

我会这样做:

import java.util.Scanner;
public class Number10 {

private static String[] nums = new String[]
        {"Zero", "One", "Two", "Three", "Four",
         "Five", "Six", "Seven", "Eight", "Nine"};

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    String num;

    System.out.print("Enter a number and i'll convert it to words: ");
    num = input.nextLine();
    input.close()

    for (Character c: num.toCharArray())
        System.out.print(nums[Character.getNumericValue(c)]+ ' ');

}
于 2014-09-21T09:42:08.113 回答
0

首先,您可以创建一个

java.util.Map<Integer, String>

保存整数值到字符串表示的映射,但这只会缩短您的代码。下一步是按数字处理数字,因此您可以保存数字到字符串表示的映射并打印每个数字的字符串表示:

Map<Integer, String> numbers = new HashMap<Integer, String>();
numbers.put(0, "Zero");
// 22 = numbers.get(2) + " " + numbers.get(2);
// 51 = numbers.get(5) + " " + numbers.get(1);
// ...
于 2014-09-21T09:33:19.827 回答
0

使用HashMap<Integer,String>. 这使得代码更简洁,更灵活。例如,如果您还想为其他语言添加功能。

使用循环来填充 HashMap .put(),可能来自文件。然后用于.get()检索翻译。

于 2014-09-21T09:34:26.390 回答