在这里使用简单的选择循环效果很好。这是完成的代码片段:
def run(self, resolvers_iter):
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM, 0)
sock.setblocking(False)
try:
pending = []
# For rate limiting
limit = float(self.timeout)/self.max_pending # delay between sends
last_sent = clock() - limit
# Work as long as there are more resolvers to query
completed_sending = False
while not completed_sending or pending:
# Can I send more requests
want_to_write = False
if not completed_sending and len(pending) < self.max_pending:
want_to_write = True
# Calculate nearest timeout time to make sure select returns on time
timeout = None
if pending:
timeout = self.timeout - clock() + pending[0][0] + 0.001
timeout = max(timeout, 0)
# Rate limit
time_passed_since_send = clock() - last_sent
if want_to_write and time_passed_since_send + 0.001 < limit:
timeout = min(timeout, limit-time_passed_since_send)
timeout = max(timeout, 0)
want_to_write = False
# Poll socket - uses internally the select module
readable, writable = self._select(readable=True, writable=want_to_write, timeout=timeout)
# Can read
if readable:
# Read as many as possible
while True:
try:
# Get response
response, from_address = DnsFacilities.read_response(sock)
# Check if not duplicate or already timed out
sent_time = None
for i, (t, ip) in enumerate(pending):
if ip == from_address[0]:
sent_time = t
del pending[i]
break
if sent_time is not None:
self.response_received((response, from_address, clock()-sent_time))
except socket.error, e:
if e[0] in (socket.errno.EWOULDBLOCK, socket.errno.EAGAIN):
break
elif e[0] in (socket.errno.WSAECONNRESET, socket.errno.WSAENETRESET):
pass
else:
raise
# Can write
if writable:
try:
last_sent = clock()
resolver_address = resolvers_iter.next()
DnsFacilities.send_query(resolver_address)
pending.append((clock(), resolver_address)
except StopIteration:
completed_sending = True
# Check for timed out tasks
now = clock()
while pending and now - pending[0][0] > self.timeout:
self.response_timeout(pending[0][1])
del pending[0]
finally:
sock.close()