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我正在尝试使用下拉菜单使报告像 2 个单独的报告一样。这是一个名为 rtype 的参数，其值为 0-2。

数据是客户预约，我试图报告他们保持预约的能力。

选项 1 和 2 我们正在专门寻找他们的第一次约会，因此在 where 的“不存在”部分中，子查询正在寻找以前的约会。

清单 3 本质上是 list1+list2（还有更多），但我们不在乎它是否是初次约会

select sa.organization, sa.status, count(1)
 from mytable as sa
where  sa.service_date between  ${sdate} and ${edate}
 and (
	(${rtype}::int = 0 and sa.activity_id in (..) /*list 1*/ )
	OR(${rtype}::int = 1 and sa.activity_id in (..)  /*list 2*/)
	OR(${rtype}::int = 2 AND sa.activity_id not in (..) /*list 3*/)
)

and ( 
	(${rtype}::int !=2 AND not exists (select *
                     from rpt_scheduled_activities as sa2
                    where sa2.client_id = sa.client_id
                      and (   
							(${rtype}::int = 0 and sa.activity_id in (..)/*list 1*/ )
							OR
							(${rtype}::int = 1 and sa.activity_id in (..)  /*list 1*/ )
							)
                      and sa2.status in ('Kept')
					  and sa2.service_date <  sa.service_date
                      ))
       OR (${rtype}::int = 2))
     
group by 
		sa.organization,
          sa.status
order by 
		 sa.status

本质上，我想在 rtype = 2 时“跳过”不存在的子查询。

谁能指出我做错了什么？

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0 回答 0