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我正在尝试让 Flask-openid 正常工作，但在尝试登录时一直遇到此错误

ValueError: Unicode strings with encoding declaration are not supported. Please use bytes input or XML fragments without declaration.

使用此功能时会发生

oid.try_login(openid, ask_for=['email', 'fullname', 'nickname'])

这是使用该功能的地方：

@app.route('/login', methods=['GET', 'POST'])
@oid.loginhandler
def login():
    """Does the login via OpenID.  Has to call into `oid.try_login`
    to start the OpenID machinery.
    """
    # if we are already logged in, go back to were we came from
    if g.user is not None:
        app.logger.info('logged-in: ' + oid.get_next_url())
        return redirect(oid.get_next_url())
    if request.method == 'POST':
        openid = request.form.get('openid_identifier')
        if openid:
            app.logger.info(request.form)
            app.logger.info('logging-in: ' + oid.get_next_url())
            return oid.try_login(openid, ask_for=['email', 'fullname',
                                                  'nickname'])
    app.logger.info('not-logged-in: ' + oid.get_next_url())
    return render_template('login.html', next=oid.get_next_url(),
                           error=oid.fetch_error())

实际上似乎是 Flask-openid 使用的 lxml 的问题：

  File "C:\Python33\lib\site-packages\openid\yadis\etxrd.py", line 69, in parseXRDS
    element = ElementTree.XML(text)
  File "lxml.etree.pyx", line 3012, in lxml.etree.XML (src\lxml\lxml.etree.c:67876) 
  File "parser.pxi", line 1781, in lxml.etree._parseMemoryDocument (src\lxml\lxml.etree.c:102435)

我在 github 上尝试了几个示例项目，但它们都有相同的问题。有什么方法可以让 Flask-openid 在 Python 3 中工作吗？

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2 回答 2

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Its much more than just string. Its based on an older python-openid package That is not Python3 compatible. There is a new version of python-openid specifically for Python3.

https://pypi.python.org/pypi/python3-openid/3.0.1

Same blog mentioned earlier also detail this: http://blog.miguelgrinberg.com/post/the-flask-mega-tutorial-part-v-user-logins "Unfortunately version 1.2.1 of Flask-OpenID (the current official version) does not work well with Python 3. Check what version you have by running the following command:"

于 2015-01-15T23:46:44.347 回答
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我自己只是在学习 Flask，所以帮不上什么忙。

但是看看http://blog.miguelgrinberg.com/post/the-flask-mega-tutorial-part-v-user-logins

作者提到

请注意，由于 Python 2 和 3 之间 unicode 处理的差异，我们必须提供此方法的两个替代版本。

他使用 astr而不是unicode

def get_id(self):
    try:
        return unicode(self.id)  # python 2
    except NameError:
        return str(self.id)  # python 3

我可能完全错了！在这种情况下，我很抱歉，但值得一试。

于 2014-11-23T01:10:05.533 回答