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我的触发器想要检查“新”经理是否监督不超过 5 名员工。BLOCKED_MANAGER 表(ssn,numberofemployees)中仅监督 5 人的经理。最后,每个更新都记录在 SUPERLOG 表中(日期、用户、旧管理器、新管理器)。我没有收到有关触发器的编译错误,但是当我更新 superssn 时,我收到此错误:

SQL> update employee set superssn='666666607' where ssn='111111100';
update employee set superssn='666666607' where ssn='111111100'
   *
ERROR at line 1:
ORA-04091: Table FRANK.EMPLOYEE is mutating, the trigger/function
can't read it
ORA-06512: a "FRANK.TLOG", line 20
ORA-04088: error during execution of trigger 'FRANK.TLOG'

我该如何解决这个触发器?谢谢

create or replace trigger tlog 
before update of superssn on employee
for each row
declare
t1 exception;
n number:=0;
cont number:=0;
empl varchar2(16);
cursor cur is (select ssn from blocked_manager where ssn is not null);
begin
open cur;
    loop
fetch cur into empl;
exit when cur%notfound;
if(:new.superssn = empl) then
    n:=1;
end if;
end loop;
close cur;
if n=1 then
raise t1;
end if;
select count(*) into cont from employee group by superssn having superssn=:new.superssn;
if(cont=4) then
insert into blocked_manager values(:new.superssn,5);
end if;
insert into superlog values(sysdate,user,:old.superssn, :new.superssn );
exception
when t1 then
raise_application_error(-20003,'Manager '||:new.superssn||' has already 5 employees');
end;
4

2 回答 2

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正如您所发现的,您不能从定义行级触发器的同一个表中进行选择;它会导致表变异异常。

为了使用触发器正确创建此验证,应创建一个过程以获取用户指定的锁,以便验证可以在多用户环境中正确序列化。

PROCEDURE request_lock
  (p_lockname                     IN     VARCHAR2
  ,p_lockmode                     IN     INTEGER  DEFAULT dbms_lock.x_mode
  ,p_timeout                      IN     INTEGER  DEFAULT 60
  ,p_release_on_commit            IN     BOOLEAN  DEFAULT TRUE
  ,p_expiration_secs              IN     INTEGER  DEFAULT 600)
IS
  -- dbms_lock.allocate_unique issues implicit commit, so place in its own
  -- transaction so it does not affect the caller
  PRAGMA AUTONOMOUS_TRANSACTION;
  l_lockhandle                   VARCHAR2(128);
  l_return                       NUMBER;
BEGIN
  dbms_lock.allocate_unique
    (lockname                       => p_lockname
    ,lockhandle                     => p_lockhandle
    ,expiration_secs                => p_expiration_secs);
  l_return := dbms_lock.request
    (lockhandle                     => l_lockhandle
    ,lockmode                       => p_lockmode
    ,timeout                        => p_timeout
    ,release_on_commit              => p_release_on_commit);
  IF (l_return not in (0,4)) THEN
    raise_application_error(-20001, 'dbms_lock.request Return Value ' || l_return);
  END IF;
  -- Must COMMIT an autonomous transaction
  COMMIT;
END request_lock;

然后可以在复合触发器中使用此过程(假设至少是 Oracle 11,这将需要在早期版本中拆分为单独的触发器)

CREATE OR REPLACE TRIGGER too_many_employees
  FOR INSERT OR UPDATE ON employee
  COMPOUND TRIGGER

  -- Table to hold identifiers of inserted/updated employee supervisors
  g_superssns sys.odcivarchar2list;

BEFORE STATEMENT 
IS
BEGIN
  -- Reset the internal employee supervisor table
  g_superssns := sys.odcivarchar2list();
END BEFORE STATEMENT; 

AFTER EACH ROW
IS
BEGIN
  -- Store the inserted/updated supervisors of employees
  IF (  (   INSERTING
        AND :new.superssn IS NOT NULL)
     OR (   UPDATING
        AND (  :new.superssn  <> :old.superssn
            OR :new.superssn IS NOT NULL AND :old.superssn IS NULL) ) )
  THEN           
    g_superssns.EXTEND;
    g_superssns(g_superssns.LAST) := :new.superssn;
  END IF;
END AFTER EACH ROW;

AFTER STATEMENT
IS
  CURSOR csr_supervisors
  IS
    SELECT DISTINCT
           sup.column_value superssn
    FROM TABLE(g_superssns) sup
    ORDER BY sup.column_value;
  CURSOR csr_constraint_violations
    (p_superssn employee.superssn%TYPE)
  IS
    SELECT count(*) employees
    FROM employees
    WHERE pch.superssn = p_superssn
    HAVING count(*) > 5;
  r_constraint_violation csr_constraint_violations%ROWTYPE;
BEGIN
  -- Check if for any inserted/updated employee there exists more than
  -- 5 employees for the same supervisor. Serialise the constraint for each
  -- superssn so concurrent transactions do not affect each other
  FOR r_supervisor IN csr_supervisors LOOP
    request_lock('TOO_MANY_EMPLOYEES_' || r_supervisor.superssn);
    OPEN csr_constraint_violations(r_supervisor.superssn);
    FETCH csr_constraint_violations INTO r_constraint_violation;
    IF csr_constraint_violations%FOUND THEN
      CLOSE csr_constraint_violations;
      raise_application_error(-20001, 'Supervisor ' || r_supervisor.superssn || ' now has ' || r_constraint_violation.employees || ' employees');
    ELSE
      CLOSE csr_constraint_violations;
    END IF;
  END LOOP;
END AFTER STATEMENT;

END;

您不需要该blocked_manager表来管理此约束。该信息可以从employee表中得出。

或者在早于 Oracle 11i 的版本中:

CREATE OR REPLACE PACKAGE employees_trg
AS
  -- Table to hold identifiers of inserted/updated employee supervisors
  g_superssns sys.odcivarchar2list;
END employees_trg;

CREATE OR REPLACE TRIGGER employee_biu
  BEFORE INSERT OR UPDATE ON employee
IS
BEGIN
  -- Reset the internal employee supervisor table
  employees_trg.g_superssns := sys.odcivarchar2list();
END; 

CREATE OR REPLACE TRIGGER employee_aiur
  AFTER INSERT OR UPDATE ON employee
  FOR EACH ROW
IS
BEGIN
  -- Store the inserted/updated supervisors of employees
  IF (  (   INSERTING
        AND :new.superssn IS NOT NULL)
     OR (   UPDATING
        AND (  :new.superssn  <> :old.superssn
            OR :new.superssn IS NOT NULL AND :old.superssn IS NULL) ) )
  THEN           
    employees_trg.g_superssns.EXTEND;
    employees_trg.g_superssns(employees_trg.g_superssns.LAST) := :new.superssn;
  END IF;
END; 

CREATE OR REPLACE TRIGGER employee_aiu
  AFTER INSERT OR UPDATE ON employee
IS
DECLARE
  CURSOR csr_supervisors
  IS
    SELECT DISTINCT
           sup.column_value superssn
    FROM TABLE(employees_trg.g_superssns) sup
    ORDER BY sup.column_value;
  CURSOR csr_constraint_violations
    (p_superssn employee.superssn%TYPE)
  IS
    SELECT count(*) employees
    FROM employees
    WHERE pch.superssn = p_superssn
    HAVING count(*) > 5;
  r_constraint_violation csr_constraint_violations%ROWTYPE;
BEGIN
  -- Check if for any inserted/updated employee there exists more than
  -- 5 employees for the same supervisor. Serialise the constraint for each
  -- superssn so concurrent transactions do not affect each other
  FOR r_supervisor IN csr_supervisors LOOP
    request_lock('TOO_MANY_EMPLOYEES_' || r_supervisor.superssn);
    OPEN csr_constraint_violations(r_supervisor.superssn);
    FETCH csr_constraint_violations INTO r_constraint_violation;
    IF csr_constraint_violations%FOUND THEN
      CLOSE csr_constraint_violations;
      raise_application_error(-20001, 'Supervisor ' || r_supervisor.superssn || ' now has ' || r_constraint_violation.employees || ' employees');
    ELSE
      CLOSE csr_constraint_violations;
    END IF;
  END LOOP;
END;
于 2014-09-18T18:00:57.377 回答
0

解决此问题的最快方法可能是使用精心构造的语句触发器而不是行触发器。行触发器中包含短语FOR EACH ROW,为每行修改(基于触发器上的 、 和约束)调用BEFORE/AFTER INSERTBEFORE/AFTER UPDATE可以BEFORE/AFTER DELETE看到适当的 :NEW 和 :OLD 值,并且受制于“看不到在定义触发器的表上”规则。语句触发器在执行的每个语句的适当时间调用,看不到行值,但不受查看定义它们的特定表的限制。因此,对于不需要使用 :NEW 或 :OLD 值的逻辑部分,这样的触发器可能会很有用:

CREATE OR REPLACE TRIGGER EMPLOYEE_S_BU
  BEFORE UPDATE ON EMPLOYEE
  -- Note: no BEFORE EACH ROW phrase, so this is a statement trigger
BEGIN
  -- The following FOR loop should insert rows into BLOCKED_MANAGER for all
  -- supervisors which have four or more employees under them and who are not
  -- already in BLOCKED_MANAGER.

  FOR aRow IN (SELECT e.SUPERSSN, COUNT(e.SUPERSSN) AS EMP_COUNT
                 FROM EMPLOYEE e
                 LEFT OUTER JOIN BLOCKED_MANAGER b
                   ON b.SSN = e.SUPERSSN
                 WHERE b.SSN IS NULL
                 GROUP BY e.SUPERSSN
                 HAVING COUNT(e.SUPERSSN) >= 4)
  LOOP
    INSERT INTO BLOCKED_MANAGER
      (SSN, EMPLOYEE_COUNT)
    VALUES
      (aRow.SUPERSSN, aRow.EMP_COUNT);
  END LOOP;

  -- Remove rows from BLOCKED_MANAGER for managers who supervise fewer
  -- than four employees.

  FOR aRow IN (SELECT e.SUPERSSN, COUNT(e.SUPERSSN) AS EMP_COUNT
                 FROM EMPLOYEE e
                 INNER JOIN BLOCKED_MANAGER b
                   ON b.SSN = e.SUPERSSN
                 GROUP BY e.SUPERSSN
                 HAVING COUNT(e.SUPERSSN) <= 3)
  LOOP
    DELETE FROM BLOCKED_MANAGER
      WHERE SSN = aRow.SUPERSSN;
  END LOOP;      

  -- Finally, if any supervisor has five or more employees under them,
  -- raise an exception. Note that we go directly to EMPLOYEE to determine
  -- the number of employees supervised.

  FOR aRow IN (SELECT SUPERSSN, COUNT(*) AS EMP_COUNT
                 FROM EMPLOYEE
                 GROUP BY SUPERSSN
                 HAVING COUNT(*) >= 5)
  LOOP
    -- If we get here we've found a supervisor with 5 (or more) employees.
    -- Raise an exception

    RAISE_APPLICATION_ERROR(-20000, 'Found supervisor ' || aRow.SUPERSSN ||
                                    ' supervising ' || aRow.EMP_COUNT ||
                                    ' employees');
  END LOOP;
END EMPLOYEE_S_BU;

请注意,如果您摆脱 BLOCKED_MANAGER 表(此触发器仍然维护,尽管我不知道它是否真的有必要),逻辑将大大减少。

您仍然需要一个行触发器来处理日志记录,但这只是减少现有触发器的问题,我将把它留给您。:-)

分享和享受。

于 2014-09-19T02:42:40.410 回答