16

With SQLAlchemy, is there a way to know beforehand whether a relation would be lazy-loaded?
For example, given a lazy parent->children relation and an instance X of "parent", I'd like to know if "X.children" is already loaded, without triggering the query.

4

3 回答 3

23

You can get a list of all unloaded properties (both relations and columns) from sqlalchemy.orm.attributes.instance_state(obj).unloaded.

See: Completing object with its relations and avoiding unnecessary queries in sqlalchemy

An easier way is to use inspect(), which gives the same results:

from sqlalchemy import inspect
from sqlalchemy.orm import lazyload

user = session.query(User).options(lazyload(User.articles)).first()
ins = inspect(user)

ins.unloaded  # <- set or properties that are not yet loaded
于 2014-07-29T09:05:24.683 回答
5

I think you could look at the child's __dict__ attribute dictionary to check if the data is already there or not.

于 2008-11-04T07:48:26.470 回答
3

Slightly neater than Haes answer (though it effectively does the same thing) is to use hasattr(), as in:

>>> hasattr(X, 'children')
False
于 2013-01-15T10:34:28.860 回答