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我目前能够将列表保存到服务器上的 CSV 文件中,如下面的代码所示。但是,我希望 ASP.NET 应用程序通过文件保存对话框提示用户并将其保存在他的客户端系统中。因此,我在将列表绑定到 GridView 的页面的“导出到 CSV”按钮单击中有此代码。但是,此代码在 IE 中运行时会引发 JavaScript 错误,复制如下。这有什么问题?响应应该在单独的 ASPX 上吗?

 CsvContext cc = new CsvContext();
            string outputFileName = string.Format("D:\\Dashboard.csv", DateTime.Now);
            cc.Write(filteredListOfPerformanceDashboardSummary, outputFileName);
            HttpContext.Current.Response.Clear();
            HttpContext.Current.Response.ClearHeaders();
            HttpContext.Current.Response.ClearContent();
            HttpContext.Current.Response.AddHeader("content-disposition", outputFileName);
            HttpContext.Current.Response.ContentType = "text/csv";
            HttpContext.Current.Response.AddHeader("Pragma", "public");
            HttpContext.Current.Response.Write(cc.ToString());
            HttpContext.Current.Response.End();

我收到这个 IE 错误

Error: Sys.WebForms.PageRequestManagerParserErrorException: The message received from the server could not be parsed.

当我单击链接时,它会在此处出现错误

function Sys$WebForms$PageRequestManager$_endPostBack(error, executor, data) {
        if (this._request === executor.get_webRequest()) {
            this._processingRequest = false;
            this._additionalInput = null;
            this._request = null;
        }
        var handler = this._get_eventHandlerList().getHandler("endRequest");
        var errorHandled = false;
        if (handler) {
            var eventArgs = new Sys.WebForms.EndRequestEventArgs(error, data ? data.dataItems : {}, executor);
            handler(this, eventArgs);
            errorHandled = eventArgs.get_errorHandled();
        }
        if (error && !errorHandled) {
            throw error;
        }
    }
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1 回答 1

1

你可以做Responce.WriteFile

CsvContext cc = new CsvContext();
string outputFileName = string.Format("D:\\Dashboard.csv", DateTime.Now);
cc.Write(categoryList, outputFileName);  
Response.Clear();
Response.ContentType = "text/csv"; //or "application/csv" 
Response.AddHeader("Content-disposition", "attachment; filename=\"sample.csv" + "\"");
Response.WriteFile(outputFileName);
Response.Flush();
Response.End();
于 2014-09-16T04:10:25.983 回答