1

我正在尝试为此查询引入联接：

SELECT `n`.*, round((`n`.`rgt` - `n`.`lft` - 1) / 2, 0) AS childs, 
count(*) - 1 + (`n`.`lft` > 1) + 1 AS level, 
((min(`p`.`rgt`) - `n`.`rgt` - (`n`.`lft` > 1)) / 2) > 0 AS lower, 
(((`n`.`lft` - max(`p`.`lft`) > 1))) AS upper 
FROM `exp_node_tree_6` `n`, `exp_node_tree_6` `p`, `exp_node_tree_6`
WHERE `n`.`lft` 
BETWEEN `p`.`lft` 
AND `p`.`rgt` 
AND ( `p`.`node_id` != `n`.`node_id` OR `n`.`lft` = 1 )
GROUP BY `n`.`node_id` 
ORDER BY `n`.`lft`

通过添加

LEFT JOIN `exp_channel_titles`
ON (`n`.`entry_id`=`exp_channel_titles`.`entry_id`)

在 FROM 语句之后...

但是当我介绍它时，它以“'on 子句'中的未知列'n.entry_id'”失败

甚至可以向此查询添加连接吗？

谁能帮忙，谢谢！

4

1 回答 1

1

我想你的问题来自于你在表列表的末尾添加了 join 子句。尝试

SELECT `n`.*, round((`n`.`rgt` - `n`.`lft` - 1) / 2, 0) AS childs, 
count(*) - 1 + (`n`.`lft` > 1) + 1 AS level, 
((min(`p`.`rgt`) - `n`.`rgt` - (`n`.`lft` > 1)) / 2) > 0 AS lower, 
(((`n`.`lft` - max(`p`.`lft`) > 1))) AS upper 
FROM `exp_node_tree_6` `n`
     LEFT JOIN `exp_channel_titles`
     ON (`n`.`entry_id`=`exp_channel_titles`.`entry_id`),

     `exp_node_tree_6` `p`,
     `exp_node_tree_6`
WHERE `n`.`lft` 
BETWEEN `p`.`lft` 
AND `p`.`rgt` 
AND ( `p`.`node_id` != `n`.`node_id` OR `n`.`lft` = 1 )
GROUP BY `n`.`node_id` 
ORDER BY `n`.`lft`

您只能在ON子句中引用属于已在 JOIN 流中的表的字段。

我希望这会对你有所帮助，杰罗姆·瓦格纳

于 2010-04-04T13:15:52.403 回答