WKWebView
不会打开任何target="_blank"
在其 HTML 标签中具有“在新窗口中打开”属性的链接<a href>
。
15 回答
我的解决方案是取消导航并再次使用 loadRequest: 加载请求。这将出现类似 UIWebView 的行为,它总是在当前帧中打开新窗口。
实现WKUIDelegate
委托并将其设置为_webview.uiDelegate
. 然后实现:
- (WKWebView *)webView:(WKWebView *)webView createWebViewWithConfiguration:(WKWebViewConfiguration *)configuration forNavigationAction:(WKNavigationAction *)navigationAction windowFeatures:(WKWindowFeatures *)windowFeatures
{
if (!navigationAction.targetFrame.isMainFrame) {
[webView loadRequest:navigationAction.request];
}
return nil;
}
@Cloud Xu 的答案是正确答案。仅供参考,这里是 Swift:
// this handles target=_blank links by opening them in the same view
func webView(webView: WKWebView!, createWebViewWithConfiguration configuration: WKWebViewConfiguration!, forNavigationAction navigationAction: WKNavigationAction!, windowFeatures: WKWindowFeatures!) -> WKWebView! {
if navigationAction.targetFrame == nil {
webView.loadRequest(navigationAction.request)
}
return nil
}
使用最新版本的 Swift 4.2+
import WebKit
使用WKUIDelegate扩展您的课程
为 webview 设置委托
self.webView.uiDelegate = self
实现协议方法
func webView(_ webView: WKWebView, createWebViewWith configuration: WKWebViewConfiguration, for navigationAction: WKNavigationAction, windowFeatures: WKWindowFeatures) -> WKWebView? {
if navigationAction.targetFrame == nil {
webView.load(navigationAction.request)
}
return nil
}
将自己添加为WKNavigationDelegate
_webView.navigationDelegate = self;
并在委托回调decisionPolicyForNavigationAction:decisionHandler中实现以下代码:
- (void)webView:(WKWebView *)webView decidePolicyForNavigationAction:(WKNavigationAction *)navigationAction decisionHandler:(void (^)(WKNavigationActionPolicy))decisionHandler
{
//this is a 'new window action' (aka target="_blank") > open this URL externally. If we´re doing nothing here, WKWebView will also just do nothing. Maybe this will change in a later stage of the iOS 8 Beta
if (!navigationAction.targetFrame) {
NSURL *url = navigationAction.request.URL;
UIApplication *app = [UIApplication sharedApplication];
if ([app canOpenURL:url]) {
[app openURL:url];
}
}
decisionHandler(WKNavigationActionPolicyAllow);
}
PS:这段代码来自我的小项目STKWebKitViewController
,它围绕 WKWebView 包装了一个可用的 UI。
如果您已经设置了 WKWebView.navigationDelegate
WKWebView.navigationDelegate = self;
你只需要实现:
- (void)webView:(WKWebView *)webView decidePolicyForNavigationAction:(WKNavigationAction *)navigationAction decisionHandler:(void (^)(WKNavigationActionPolicy))decisionHandler
{
BOOL shouldLoad = [self shouldStartLoadWithRequest:navigationAction.request]; // check the url if necessary
if (shouldLoad && navigationAction.targetFrame == nil) {
// WKWebView ignores links that open in new window
[webView loadRequest:navigationAction.request];
}
// always pass a policy to the decisionHandler
decisionHandler(shouldLoad ? WKNavigationActionPolicyAllow : WKNavigationActionPolicyCancel);
}
这样您就不需要实现 WKUIDelegate 方法。
Cloud xu
的回答解决了我的问题。
如果有人需要等效的 Swift(4.x/5.0) 版本,这里是:
func webView(_ webView: WKWebView, createWebViewWith configuration: WKWebViewConfiguration, for navigationAction: WKNavigationAction, windowFeatures: WKWindowFeatures) -> WKWebView? {
if let frame = navigationAction.targetFrame,
frame.isMainFrame {
return nil
}
// for _blank target or non-mainFrame target
webView.load(navigationAction.request)
return nil
}
当然,你必须先设置webView.uiDelegate
。
这些解决方案都不适合我,我确实通过以下方式解决了这个问题:
1)实现WKUIDelegate
@interface ViewController () <WKNavigationDelegate, WKUIDelegate>
2)设置wkWebview的UIDelegate委托
self.wkWebview.UIDelegate = self;
3)实现createWebViewWithConfiguration方法
- (WKWebView *)webView:(WKWebView *)webView createWebViewWithConfiguration:(WKWebViewConfiguration *)configuration forNavigationAction:(WKNavigationAction *)navigationAction windowFeatures:(WKWindowFeatures *)windowFeatures {
if (!navigationAction.targetFrame.isMainFrame) {
[UIApplication sharedApplication].networkActivityIndicatorVisible = YES;
[[UIApplication sharedApplication] openURL:[navigationAction.request URL]];
}
return nil; }
我确认 Bill Weinman 的 Swift 代码是正确的。但需要提到的是,如果您像我一样是 iOS 开发新手,您还需要委托 UIDelegate 才能工作。
像这样的东西:
self.webView?.UIDelegate = self
因此,您需要在三个地方进行更改。
您还可以推送另一个视图控制器,或打开一个新选项卡等:
func webView(webView: WKWebView, createWebViewWithConfiguration configuration: WKWebViewConfiguration, forNavigationAction navigationAction: WKNavigationAction, windowFeatures: WKWindowFeatures) -> WKWebView? {
var wv: WKWebView?
if navigationAction.targetFrame == nil {
if let vc = self.storyboard?.instantiateViewControllerWithIdentifier("ViewController") as? ViewController {
vc.url = navigationAction.request.URL
vc.webConfig = configuration
wv = vc.view as? WKWebView
self.navigationController?.pushViewController(vc, animated: true)
}
}
return wv
}
在 Mobile Safari 中打开 _blank 页面,如果您使用 Swift:
webView.navigationDelegate = self
并在 WKNavigationDelegate 中实现:
func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
if navigationAction.targetFrame == nil, let url = navigationAction.request.url {
if UIApplication.shared.canOpenURL(url) {
UIApplication.shared.open(url, options: [:], completionHandler: nil)
}
}
decisionHandler(WKNavigationActionPolicy.allow)
}
这对我有用:
-(WKWebView *)webView:(WKWebView *)webView createWebViewWithConfiguration:(WKWebViewConfiguration *)configuration forNavigationAction:(WKNavigationAction *)navigationAction windowFeatures:(WKWindowFeatures *)windowFeatures {
if (!navigationAction.targetFrame.isMainFrame) {
WKWebView *newWebview = [[WKWebView alloc] initWithFrame:self.view.frame configuration:configuration];
newWebview.UIDelegate = self;
newWebview.navigationDelegate = self;
[newWebview loadRequest:navigationAction.request];
self.view = newWebview;
return newWebview;
}
return nil;
}
- (void)webView:(WKWebView *)webView decidePolicyForNavigationAction:(WKNavigationAction *)navigationAction decisionHandler:(void (^)(WKNavigationActionPolicy))decisionHandler {
decisionHandler(WKNavigationActionPolicyAllow);
}
- (void)webViewDidClose:(WKWebView *)webView {
self.view = self.webView;
}
正如你所看到的,我们在这里所做的只是webView
用新的 url 打开一个新的并控制关闭的可能性,就像你需要一个响应second webview
来显示在第一个。
我遇到了一些仅使用webView.load(navigationAction.request)
. 所以我使用创建一个新的 webView 来做,它工作得很好。
//MARK:- WKUIDelegate
func webView(_ webView: WKWebView, createWebViewWith configuration: WKWebViewConfiguration, for navigationAction: WKNavigationAction, windowFeatures: WKWindowFeatures) -> WKWebView? {
NSLog(#function)
if navigationAction.targetFrame == nil {
NSLog("=> Create a new webView")
let webView = WKWebView(frame: self.view.bounds, configuration: configuration)
webView.uiDelegate = self
webView.navigationDelegate = self
self.webView = webView
return webView
}
return nil
}
**Use following function to create web view**
func initWebView(configuration: WKWebViewConfiguration)
{
let webView = WKWebView(frame: UIScreen.main.bounds, configuration: configuration)
webView.uiDelegate = self
webView.navigationDelegate = self
view.addSubview(webView)
self.webView = webView
}
**In View Did Load:**
if webView == nil { initWebView(configuration: WKWebViewConfiguration()) }
webView?.load(url: url1)
**WKUIDelegate Method need to be implemented**
extension WebViewController: WKUIDelegate {
func webView(_ webView: WKWebView, createWebViewWith configuration: WKWebViewConfiguration, for navigationAction: WKNavigationAction, windowFeatures: WKWindowFeatures) -> WKWebView? {
// push new screen to the navigation controller when need to open url in another "tab"
print("url:\(String(describing: navigationAction.request.url?.absoluteString))")
if let url = navigationAction.request.url, navigationAction.targetFrame == nil {
let viewController = WebViewController()
viewController.initWebView(configuration: configuration)
viewController.url1 = url
DispatchQueue.main.async { [weak self] in
self?.navigationController?.pushViewController(viewController, animated: true)
}
return viewController.webView
}
return nil
}
}
extension WKWebView
{
func load(url: URL) { load(URLRequest(url: url)) }
}
使用此方法在网页视图中下载 pdf
func webView(_ webView: WKWebView, createWebViewWith configuration: WKWebViewConfiguration, for navigationAction: WKNavigationAction, windowFeatures: WKWindowFeatures) -> WKWebView?