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我正在尝试在 PowerShell 中创建一个 UI，它具有DataGrid随着源更新而更新的 UI，所以我使用的是ObservableCollection<PSObject>. 但是当我将它设置为ItemsSource, 时DataGrid不会生成任何列。如果我使用原始数组，它确实如此。这是一个例子：

Add-Type -AssemblyName PresentationCore
Add-Type -AssemblyName PresentationFramework
Add-Type -AssemblyName WindowsBase

[xml]$xaml = @"
<Window xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        Title="MainWindow"
        Height="500"
        Width="600">
  <Grid>
    <Grid.RowDefinitions>
        <RowDefinition Height="*" />
        <RowDefinition Height="*" />
    </Grid.RowDefinitions>
    <DataGrid Grid.Row="0"
              x:Name="dataGrid" 
              IsReadOnly="True"
              Margin="6" />
    <DataGrid Grid.Row="1"
              x:Name="observableDataGrid" 
              IsReadOnly="True"
              Margin="6" />
  </Grid>
</Window>
"@

$reader = (New-Object System.Xml.XmlNodeReader $xaml)
$Window = [Windows.Markup.XamlReader]::Load($reader)

$dataGrid = $window.FindName("dataGrid")
$observableDataGrid = $window.FindName("observableDataGrid")

$results = Get-Process | Select-Object -Property ProcessName,Id,Handles,NPM,PM,VM,WS

$results2 = New-Object -TypeName System.Collections.ObjectModel.ObservableCollection[PSObject] -ArgumentList @(,$results)

$dataGrid.ItemsSource = $results
$observableDataGrid.ItemsSource = $results2

$Window.ShowDialog() | Out-Null
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1 回答 1

2

解决方案是将 替换ObservableCollection<PSObject>为ObservableCollection<Object>.

于 2014-09-03T07:19:45.797 回答