0

我有一个螺栓正在为每个元组进行 API 调用(HTTP Get)。为了避免需要等待响应,我希望使用 apache HttpAsyncClient。

在 Bolt 的 prepare 方法中实例化客户端后,execute 方法从元组构造 URL 并调用 sendAsyncGetRequest(url):

private void sendAsyncGetRequest(String url){

    httpclient.execute(new HttpGet(url), new FutureCallback<HttpResponse>() {

        @Override
        public void completed(HttpResponse response) {
            LOG.info("Response Code : " + response.getStatusLine());
            LOG.debug(response.toString());
        }

        @Override
        public void failed(Exception ex) {
            LOG.warn("Async http request failed!", ex);
        }

        @Override
        public void cancelled() {
            LOG.warn("Async http request canceled!");
        }
    });
}

拓扑已部署,但 Storm UI 显示错误:

java.lang.RuntimeException: java.lang.IllegalStateException: Request cannot be executed; I/O reactor status: STOPPED at backtype.storm.utils.DisruptorQueue.consumeBatchToCursor(DisruptorQueue.java:12
4

2 回答 2

0

我让这个工作没有问题。需要注意的关键事项是:

  1. 在螺栓类范围内声明客户端

    public class MyRichBolt extends BaseRichBolt {
        private CloseableHttpAsyncClient httpclient; 
    
  2. 在 Bolt 的 prepare 方法中实例化和统计客户端

    @Override
    public final void prepare(Map stormConf, TopologyContext context, OutputCollector collector) {
        try {
            // start the http client
            httpclient = HttpAsyncClients.createDefault();
            httpclient.start();
            // other initialization code ... 
        } catch (Throwable exception) {
        // handle errors
        }
    }
    
  3. 在螺栓的执行方法中进行调用

    @Override
    public final void execute(Tuple tuple) {
        // format the request url
        String url = ... 
        sendAsyncGetRequest(url);
    }
    
    
    private void sendAsyncGetRequest(String url){
        logger.debug("Async call to URL...");
        HttpGet request = new HttpGet(url);
        HttpAsyncRequestProducer producer = HttpAsyncMethods.create(request);
        AsyncCharConsumer<HttpResponse> consumer = new AsyncCharConsumer<HttpResponse>() {
    
            HttpResponse response;
    
            @Override
            protected void onResponseReceived(final HttpResponse response) {
            this.response = response;
            }
    
            @Override
            protected void onCharReceived(final CharBuffer buf, final IOControl ioctrl) throws IOException {
                // Do something useful
            }
    
            @Override
            protected void releaseResources() {
            }
    
            @Override
            protected HttpResponse buildResult(final HttpContext context) {
                return this.response;
            }
        };
    
        httpclient.execute(producer, consumer, new FutureCallback<HttpResponse>() {
    
            @Override
            public void completed(HttpResponse response) {
                // do something useful with the response
                logger.debug(response.toString());
            }
    
            @Override
            public void failed(Exception ex) {
                logger.warn("!!! Async http request failed!", ex);
            }
    
            @Override
            public void cancelled() {
                logger.warn("Async http request canceled!");
            }
        });
    }
    
于 2014-12-15T02:42:47.000 回答
0

您是否在执行回调之前关闭了主要流程中的客户端 (client.close();)?

错误是说 IO 路径已经关闭。一般来说,异步客户端的实例应该重新用于重复请求,并且仅在发出“所有”请求时销毁,例如在应用程序关闭时。

于 2016-06-26T13:25:39.920 回答