5

我正在开发一个Adob​​e Echosign演示 C# winforms 应用程序。我的代码是他们命令行代码的直接副本（有修改），但是，我的代码在传输数据后返回错误。

这是来自EchoSign的 命令行代码

public static void sendDocument(string apiKey, string fileName, string formFieldLayerTemplateKey, string recipient)
{
    FileStream file = getTestPdfFile(fileName);
    secure.echosign.com.FileInfo[] fileInfos = new secure.echosign.com.FileInfo[1];
    fileInfos[0] = new secure.echosign.com.FileInfo(fileName, null, file);
    SenderInfo senderInfo = null;
    string[] recipients = new string[1];
    recipients[0] = recipient;
    DocumentCreationInfo documentInfo = new DocumentCreationInfo(
        recipients,
        testPrefix + Path.GetFileName(file.Name),
        testMessage,
        fileInfos,
        SignatureType.ESIGN,
        SignatureFlow.SENDER_SIGNATURE_NOT_REQUIRED
    );
    if (formFieldLayerTemplateKey != null)
    {
        secure.echosign.com.FileInfo[] formFieldLayerTemplates = new secure.echosign.com.FileInfo[1];
        formFieldLayerTemplates[0] = new secure.echosign.com.FileInfo(formFieldLayerTemplateKey);
        documentInfo.formFieldLayerTemplates = formFieldLayerTemplates;
    }
    DocumentKey[] documentKeys;
    documentKeys = ES.sendDocument(apiKey, senderInfo, documentInfo);
    Console.WriteLine("Document key is: " + documentKeys[0].documentKey);
}

这是我的代码块，它从他们的系统返回错误： 

public static void sendDocument(string apiKey, string fileName, string formFieldLayerTemplateKey, string recipient)
{
    try
    {
        SenderInfo senderInfo = new SenderInfo();
        senderInfo = null;

        FileStream FileToSign = getTestPdfFile(fileName);
        byte[] bytes = System.IO.File.ReadAllBytes("C:\\PROJECTS\\TestFile.pdf");


        secure.echosign.com.FileInfo[] fileInfos = new secure.echosign.com.FileInfo[1];
        fileInfos[0] = new EchoSignTest.secure.echosign.com.FileInfo();
        fileInfos[0].fileName = fileName;
        fileInfos[0].mimeType = null;
        fileInfos[0].file = bytes;

        RecipientInfo[] docRecipient = new RecipientInfo[1];
        docRecipient[0] = new RecipientInfo();
        docRecipient[0].email = recipient;

        DocumentCreationInfo documentInfo = new DocumentCreationInfo();
        documentInfo.recipients = docRecipient;
        documentInfo.name = testPrefix + Path.GetFileName(FileToSign.Name);
        documentInfo.message = testMessage;
        documentInfo.fileInfos = fileInfos;
        documentInfo.signatureType = SignatureType.ESIGN;
        documentInfo.signatureFlow = SignatureFlow.SENDER_SIGNATURE_NOT_REQUIRED;

        if (formFieldLayerTemplateKey != null)
        {
            secure.echosign.com.FileInfo[] formFieldLayerTemplates = new secure.echosign.com.FileInfo[1];

            formFieldLayerTemplates[0] = new secure.echosign.com.FileInfo();
            formFieldLayerTemplates[0].formKey = formFieldLayerTemplateKey;
            documentInfo.formFieldLayerTemplates = formFieldLayerTemplates;
        }

        EchoSignDocumentService19PortTypeClient ES = new EchoSignDocumentService19PortTypeClient();
        DocumentKey[] documentKeys = new DocumentKey[1];

        documentKeys = ES.sendDocument(apiKey, senderInfo, documentInfo);
        Console.WriteLine("Document key is: " + documentKeys[0].documentKey);
    }
    catch (NullReferenceException ex)
    {
        string errMessage = ex.Message;
    }

    catch (Exception ex)
    {
        string errMessage = ex.Message;
    }
}

这两个代码块有什么不同？错误可能存在于FileInfo[]或DocumentCreationInfo()块中。我可能没有按照系统的要求创建对象。

任何建议表示赞赏。

4

1 回答 1

1

该错误似乎是将您读取的文档字节直接分配给fileInfos[0].file变量。在FileInfo 的文档中，它声明文件参数必须是使用 base64 编码的原始文件内容，但是您分配原始文件内容而不对其进行编码。当使用第一个示例（命令行示例）中的文件流调用构造函数时，构造函数似乎会自动处理此问题。您可以尝试在 Winforms 示例中更改这些行：

    FileStream FileToSign = getTestPdfFile(fileName);
    byte[] bytes = System.IO.File.ReadAllBytes("C:\\PROJECTS\\TestFile.pdf");


    secure.echosign.com.FileInfo[] fileInfos = new secure.echosign.com.FileInfo[1];
    fileInfos[0] = new EchoSignTest.secure.echosign.com.FileInfo();
    fileInfos[0].fileName = fileName;
    fileInfos[0].mimeType = null;
    fileInfos[0].file = bytes;

进入此代码并尝试是否可行：

    FileStream FileToSign = getTestPdfFile(fileName);


    secure.echosign.com.FileInfo[] fileInfos = new secure.echosign.com.FileInfo[1];
    fileInfos[0] = new secure.echosign.com.FileInfo(fileName, null, FileToSign);

您应该使用提供的构造函数而不是直接赋值来确保正确处理所有变量/参数。

您在评论中提到的关于不带 3 个参数的构造函数的错误可能是EchoSignTest.构造函数调用之前的前缀的结果，因为这似乎是您自己程序的命名空间，而不是所提供 API 的正确命名空间。

于 2014-11-04T11:45:28.363 回答