139

我正在将应用程序从 Objective-C 切换到 Swift,我有几个具有存储属性的类别,例如:

@interface UIView (MyCategory)

- (void)alignToView:(UIView *)view
          alignment:(UIViewRelativeAlignment)alignment;
- (UIView *)clone;

@property (strong) PFObject *xo;
@property (nonatomic) BOOL isAnimating;

@end

由于 Swift 扩展不接受这样的存储属性,我不知道如何保持与 Objc 代码相同的结构。存储属性对我的应用程序非常重要,我相信 Apple 一定已经为在 Swift 中创建了一些解决方案。

正如jou所说,我正在寻找的实际上是使用关联对象,所以我做了(在另一个上下文中):

import Foundation
import QuartzCore
import ObjectiveC

extension CALayer {
    var shapeLayer: CAShapeLayer? {
        get {
            return objc_getAssociatedObject(self, "shapeLayer") as? CAShapeLayer
        }
        set(newValue) {
            objc_setAssociatedObject(self, "shapeLayer", newValue, UInt(OBJC_ASSOCIATION_RETAIN))
        }
    }

    var initialPath: CGPathRef! {
        get {
            return objc_getAssociatedObject(self, "initialPath") as CGPathRef
        }
        set {
            objc_setAssociatedObject(self, "initialPath", newValue, UInt(OBJC_ASSOCIATION_RETAIN))
        }
    }
}

但是我在做的时候得到一个 EXC_BAD_ACCESS:

class UIBubble : UIView {
    required init(coder aDecoder: NSCoder) {
        ...
        self.layer.shapeLayer = CAShapeLayer()
        ...
    }
}

有任何想法吗?

4

19 回答 19

191

与在 Objective-C 中一样,您不能将存储的属性添加到现有的类中。如果你正在扩展一个 Objective-C 类(UIView绝对是一个),你仍然可以使用Associated Objects来模拟存储的属性:

斯威夫特 1

import ObjectiveC

private var xoAssociationKey: UInt8 = 0

extension UIView {
    var xo: PFObject! {
        get {
            return objc_getAssociatedObject(self, &xoAssociationKey) as? PFObject
        }
        set(newValue) {
            objc_setAssociatedObject(self, &xoAssociationKey, newValue, objc_AssociationPolicy(OBJC_ASSOCIATION_RETAIN))
        }
    }
}

关联键是一个指针,对于每个关联应该是唯一的。为此,我们创建了一个私有全局变量,并使用它的内存地址作为&操作符的键。有关如何在 Swift 中处理指针的更多详细信息,请参阅Using Swift with Cocoa and Objective-C 。

为 Swift 2 和 3 更新

import ObjectiveC

private var xoAssociationKey: UInt8 = 0

extension UIView {
    var xo: PFObject! {
        get {
            return objc_getAssociatedObject(self, &xoAssociationKey) as? PFObject
        }
        set(newValue) {
            objc_setAssociatedObject(self, &xoAssociationKey, newValue, objc_AssociationPolicy.OBJC_ASSOCIATION_RETAIN)
        }
    }
}

为 Swift 4 更新

在 Swift 4 中,它要简单得多。Holder 结构将包含我们的计算属性将向世界公开的私有值,从而产生存储属性行为的错觉。

资源

extension UIViewController {
    struct Holder {
        static var _myComputedProperty:Bool = false
    }
    var myComputedProperty:Bool {
        get {
            return Holder._myComputedProperty
        }
        set(newValue) {
            Holder._myComputedProperty = newValue
        }
    }
}
于 2014-08-21T13:46:06.783 回答
57

关联对象 API 使用起来有点麻烦。您可以使用辅助类删除大部分样板。

public final class ObjectAssociation<T: AnyObject> {

    private let policy: objc_AssociationPolicy

    /// - Parameter policy: An association policy that will be used when linking objects.
    public init(policy: objc_AssociationPolicy = .OBJC_ASSOCIATION_RETAIN_NONATOMIC) {

        self.policy = policy
    }

    /// Accesses associated object.
    /// - Parameter index: An object whose associated object is to be accessed.
    public subscript(index: AnyObject) -> T? {

        get { return objc_getAssociatedObject(index, Unmanaged.passUnretained(self).toOpaque()) as! T? }
        set { objc_setAssociatedObject(index, Unmanaged.passUnretained(self).toOpaque(), newValue, policy) }
    }
}

前提是您可以以更易读的方式将属性“添加”到objective-c 类:

extension SomeType {

    private static let association = ObjectAssociation<NSObject>()

    var simulatedProperty: NSObject? {

        get { return SomeType.association[self] }
        set { SomeType.association[self] = newValue }
    }
}

至于解决方案:

extension CALayer {

    private static let initialPathAssociation = ObjectAssociation<CGPath>()
    private static let shapeLayerAssociation = ObjectAssociation<CAShapeLayer>()

    var initialPath: CGPath! {
        get { return CALayer.initialPathAssociation[self] }
        set { CALayer.initialPathAssociation[self] = newValue }
    }

    var shapeLayer: CAShapeLayer? {
        get { return CALayer.shapeLayerAssociation[self] }
        set { CALayer.shapeLayerAssociation[self] = newValue }
    }
}
于 2017-03-27T20:39:00.053 回答
38

所以我想我找到了一种比上述方法更干净的方法,因为它不需要任何全局变量。我从这里得到它:http: //nshipster.com/swift-objc-runtime/

要点是您使用这样的结构:

extension UIViewController {
    private struct AssociatedKeys {
        static var DescriptiveName = "nsh_DescriptiveName"
    }

    var descriptiveName: String? {
        get {
            return objc_getAssociatedObject(self, &AssociatedKeys.DescriptiveName) as? String
        }
        set {
            if let newValue = newValue {
                objc_setAssociatedObject(
                    self,
                    &AssociatedKeys.DescriptiveName,
                    newValue as NSString?,
                    UInt(OBJC_ASSOCIATION_RETAIN_NONATOMIC)
                )
            }
        }
    }
}

更新 Swift 2

private struct AssociatedKeys {
    static var displayed = "displayed"
}

//this lets us check to see if the item is supposed to be displayed or not
var displayed : Bool {
    get {
        guard let number = objc_getAssociatedObject(self, &AssociatedKeys.displayed) as? NSNumber else {
            return true
        }
        return number.boolValue
    }

    set(value) {
        objc_setAssociatedObject(self,&AssociatedKeys.displayed,NSNumber(bool: value),objc_AssociationPolicy.OBJC_ASSOCIATION_RETAIN_NONATOMIC)
    }
}
于 2015-08-17T23:18:33.700 回答
17

jou指出的解决方案不支持值类型,这也适用于它们

包装纸

import ObjectiveC

final class Lifted<T> {
    let value: T
    init(_ x: T) {
        value = x
    }
}

private func lift<T>(x: T) -> Lifted<T>  {
    return Lifted(x)
}

func setAssociatedObject<T>(object: AnyObject, value: T, associativeKey: UnsafePointer<Void>, policy: objc_AssociationPolicy) {
    if let v: AnyObject = value as? AnyObject {
        objc_setAssociatedObject(object, associativeKey, v,  policy)
    }
    else {
        objc_setAssociatedObject(object, associativeKey, lift(value),  policy)
    }
}

func getAssociatedObject<T>(object: AnyObject, associativeKey: UnsafePointer<Void>) -> T? {
    if let v = objc_getAssociatedObject(object, associativeKey) as? T {
        return v
    }
    else if let v = objc_getAssociatedObject(object, associativeKey) as? Lifted<T> {
        return v.value
    }
    else {
        return nil
    }
}

可能的 类扩展(使用示例):

extension UIView {

    private struct AssociatedKey {
        static var viewExtension = "viewExtension"
    }

    var referenceTransform: CGAffineTransform? {
        get {
            return getAssociatedObject(self, associativeKey: &AssociatedKey.viewExtension)
        }

        set {
            if let value = newValue {
                setAssociatedObject(self, value: value, associativeKey: &AssociatedKey.viewExtension, policy: objc_AssociationPolicy.OBJC_ASSOCIATION_RETAIN_NONATOMIC)
            }
        }
    }
}

这真的是一个很棒的解决方案,我想添加另一个使用示例,其中包括不是可选的结构和值。此外,可以简化 AssociatedKey 值。

struct Crate {
    var name: String
}

class Box {
    var name: String

    init(name: String) {
        self.name = name
    }
}

extension UIViewController {

    private struct AssociatedKey {
        static var displayed:   UInt8 = 0
        static var box:         UInt8 = 0
        static var crate:       UInt8 = 0
    }

    var displayed: Bool? {
        get {
            return getAssociatedObject(self, associativeKey: &AssociatedKey.displayed)
        }

        set {
            if let value = newValue {
                setAssociatedObject(self, value: value, associativeKey: &AssociatedKey.displayed, policy: objc_AssociationPolicy.OBJC_ASSOCIATION_RETAIN_NONATOMIC)
            }
        }
    }

    var box: Box {
        get {
            if let result:Box = getAssociatedObject(self, associativeKey: &AssociatedKey.box) {
                return result
            } else {
                let result = Box(name: "")
                self.box = result
                return result
            }
        }

        set {
            setAssociatedObject(self, value: newValue, associativeKey: &AssociatedKey.box, policy: objc_AssociationPolicy.OBJC_ASSOCIATION_RETAIN_NONATOMIC)
        }
    }

    var crate: Crate {
        get {
            if let result:Crate = getAssociatedObject(self, associativeKey: &AssociatedKey.crate) {
                return result
            } else {
                let result = Crate(name: "")
                self.crate = result
                return result
            }
        }

        set {
            setAssociatedObject(self, value: newValue, associativeKey: &AssociatedKey.crate, policy: objc_AssociationPolicy.OBJC_ASSOCIATION_RETAIN_NONATOMIC)
        }
    }
}
于 2015-04-15T22:50:50.557 回答
14

您不能使用新存储定义类别(Swift 扩展);必须计算而不是存储任何其他属性。该语法适用于 Objective C,因为@property在一个类别中本质上意味着“我将提供 getter 和 setter”。在 Swift 中,你需要自己定义这些来获得一个计算属性;就像是:

extension String {
    public var Foo : String {
        get
        {
            return "Foo"
        }

        set
        {
            // What do you want to do here?
        }
    }
}

应该可以正常工作。请记住,您不能在 setter 中存储新值,只能使用现有的可用类状态。

于 2014-08-21T12:56:31.550 回答
7

我的 0.02 美元。这段代码是用Swift 2.0编写的

extension CALayer {
    private struct AssociatedKeys {
        static var shapeLayer:CAShapeLayer?
    }

    var shapeLayer: CAShapeLayer? {
        get {
            return objc_getAssociatedObject(self, &AssociatedKeys.shapeLayer) as? CAShapeLayer
        }
        set {
            if let newValue = newValue {
                objc_setAssociatedObject(self, &AssociatedKeys.shapeLayer, newValue as CAShapeLayer?, objc_AssociationPolicy.OBJC_ASSOCIATION_RETAIN_NONATOMIC)
            }
        }
    }
}

我尝试了很多解决方案,发现这是使用额外变量参数实际扩展类的唯一方法。

于 2015-08-27T15:35:46.603 回答
6

为什么要依赖 objc 运行时?我不明白这一点。通过使用类似以下的内容,您将实现与存储属性几乎相同的行为,仅使用纯 Swift 方法

extension UIViewController {
    private static var _myComputedProperty = [String:Bool]()

    var myComputedProperty:Bool {
        get {
            let tmpAddress = String(format: "%p", unsafeBitCast(self, to: Int.self))
            return UIViewController._myComputedProperty[tmpAddress] ?? false
        }
        set(newValue) {
            let tmpAddress = String(format: "%p", unsafeBitCast(self, to: Int.self))
            UIViewController._myComputedProperty[tmpAddress] = newValue
        }
    }
}
于 2018-03-28T21:08:27.820 回答
5

我更喜欢用纯 Swift 编写代码,而不是依赖于 Objective-C 的传统。因此,我编写了具有两个优点和两个缺点的纯 Swift 解决方案。

优点:

  1. 纯 Swift 代码

  2. 适用于类和完成或更具体地适用于Any对象

缺点:

  1. 代码应该调用方法willDeinit()来释放链接到特定类实例的对象以避免内存泄漏

  2. 对于这个确切的示例,您不能直接对 UIView 进行扩展,因为var frame它是对 UIView 的扩展,而不是类的一部分。

编辑:

import UIKit

var extensionPropertyStorage: [NSObject: [String: Any]] = [:]

var didSetFrame_ = "didSetFrame"

extension UILabel {

    override public var frame: CGRect {

        get {
            return didSetFrame ?? CGRectNull
        }

        set {
            didSetFrame = newValue
        }
    }

    var didSetFrame: CGRect? {

        get {
            return extensionPropertyStorage[self]?[didSetFrame_] as? CGRect
        }

        set {
            var selfDictionary = extensionPropertyStorage[self] ?? [String: Any]()

            selfDictionary[didSetFrame_] = newValue

            extensionPropertyStorage[self] = selfDictionary
        }
    }

    func willDeinit() {
        extensionPropertyStorage[self] = nil
    }
}
于 2015-07-22T16:31:49.157 回答
3

使用 Obj-c 类别,您只能添加方法,不能添加实例变量。

在您的示例中,您使用 @property 作为添加 getter 和 setter 方法声明的快捷方式。您仍然需要实现这些方法。

同样,在 Swift 中,您可以添加使用扩展来添加实例方法、计算属性等,但不能添加存储属性。

于 2014-08-21T13:01:50.113 回答
3

注意:经过进一步分析,下面的代码可以正常工作,但不会释放视图对象,所以如果我能找到解决方法,我会编辑答案。同时,阅读评论。

如何将静态映射存储到像这样扩展的类:

extension UIView {
    
    struct Holder {
        static var _padding:[UIView:UIEdgeInsets] = [:]
    }
   
    var padding : UIEdgeInsets {
        get{ return UIView.Holder._padding[self] ?? .zero}
        set { UIView.Holder._padding[self] = newValue }
    }

}
于 2019-06-24T07:22:32.603 回答
2

我也遇到了 EXC_BAD_ACCESS 问题。objc_getAssociatedObject()和中的值objc_setAssociatedObject()应该是一个对象。并且objc_AssociationPolicy应该匹配对象。

于 2016-02-15T08:26:01.783 回答
2

我尝试使用此处的一些答案中提到的 objc_setAssociatedObject ,但是在几次失败后我退后一步,意识到我没有理由需要它。借用这里的一些想法,我想出了这段代码,它简单地存储了一个数组,其中包含我想要关联的对象索引的任何我的额外数据(在本例中为 MyClass):

class MyClass {
    var a = 1
    init(a: Int)
    {
        self.a = a
    }
}

extension UIView
{
    static var extraData = [UIView: MyClass]()

    var myClassData: MyClass? {
        get {
            return UIView.extraData[self]
        }
        set(value) {
            UIView.extraData[self] = value
        }
    }
}

// Test Code: (Ran in a Swift Playground)
var view1 = UIView()
var view2 = UIView()

view1.myClassData = MyClass(a: 1)
view2.myClassData = MyClass(a: 2)
print(view1.myClassData?.a)
print(view2.myClassData?.a)
于 2016-08-08T01:14:01.460 回答
2

这是简化且更具表现力的解决方案。它适用于值和引用类型。提升的方法取自@HepaKKes 的回答。

协会代码:

import ObjectiveC

final class Lifted<T> {
    let value: T
    init(_ x: T) {
        value = x
    }
}

private func lift<T>(_ x: T) -> Lifted<T>  {
    return Lifted(x)
}

func associated<T>(to base: AnyObject,
                key: UnsafePointer<UInt8>,
                policy: objc_AssociationPolicy = .OBJC_ASSOCIATION_RETAIN,
                initialiser: () -> T) -> T {
    if let v = objc_getAssociatedObject(base, key) as? T {
        return v
    }

    if let v = objc_getAssociatedObject(base, key) as? Lifted<T> {
        return v.value
    }

    let lifted = Lifted(initialiser())
    objc_setAssociatedObject(base, key, lifted, policy)
    return lifted.value
}

func associate<T>(to base: AnyObject, key: UnsafePointer<UInt8>, value: T, policy: objc_AssociationPolicy = .OBJC_ASSOCIATION_RETAIN) {
    if let v: AnyObject = value as AnyObject? {
        objc_setAssociatedObject(base, key, v, policy)
    }
    else {
        objc_setAssociatedObject(base, key, lift(value), policy)
    }
}

使用示例:

1) 创建扩展并将属性与其关联。让我们同时使用值和引用类型属性。

extension UIButton {

    struct Keys {
        static fileprivate var color: UInt8 = 0
        static fileprivate var index: UInt8 = 0
    }

    var color: UIColor {
        get {
            return associated(to: self, key: &Keys.color) { .green }
        }
        set {
            associate(to: self, key: &Keys.color, value: newValue)
        }
    }

    var index: Int {
        get {
            return associated(to: self, key: &Keys.index) { -1 }
        }
        set {
            associate(to: self, key: &Keys.index, value: newValue)
        }
    }

}

2)现在您可以像常规属性一样使用:

    let button = UIButton()
    print(button.color) // UIExtendedSRGBColorSpace 0 1 0 1 == green
    button.color = .black
    print(button.color) // UIExtendedGrayColorSpace 0 1 == black

    print(button.index) // -1
    button.index = 3
    print(button.index) // 3

更多细节:

  1. 包装值类型需要提升。
  2. 默认关联对象行为是保留。如果您想了解有关关联对象的更多信息,我建议您查看这篇文章
于 2017-01-26T09:22:40.957 回答
2

如果您希望为 UIView 设置自定义字符串属性,这就是我在 Swift 4 上所做的

创建一个 UIView 扩展

extension UIView {

    func setStringValue(value: String, key: String) {
        layer.setValue(value, forKey: key)
    }

    func stringValueFor(key: String) -> String? {
        return layer.value(forKey: key) as? String
    }
}

使用此扩展程序

let key = "COLOR"

let redView = UIView() 

// To set
redView.setStringAttribute(value: "Red", key: key)

// To read
print(redView.stringValueFor(key: key)) // Optional("Red")
于 2019-01-30T04:33:37.633 回答
2

在带有WEAK参考处理的PURE SWIFT中

import Foundation
import UIKit

extension CustomView {
    
    // can make private
    static let storedProperties = WeakDictionary<UIView, Properties>()
    
    struct Properties {
        var url: String = ""
        var status = false
        var desc: String { "url: \(url), status: \(status)" }
    }
    
    var properties: Properties {
        get {
            return CustomView.storedProperties.get(forKey: self) ?? Properties()
        }
        set {
            CustomView.storedProperties.set(forKey: self, object: newValue)
        }
    }
}

var view: CustomView? = CustomView()
print("1 print", view?.properties.desc ?? "nil")
view?.properties.url = "abc"
view?.properties.status = true
print("2 print", view?.properties.desc ?? "nil")
view = nil

弱字典.swift

import Foundation

private class WeakHolder<T: AnyObject>: Hashable {
    weak var object: T?
    let hash: Int

    init(object: T) {
        self.object = object
        hash = ObjectIdentifier(object).hashValue
    }

    func hash(into hasher: inout Hasher) {
        hasher.combine(hash)
    }

    static func ==(lhs: WeakHolder, rhs: WeakHolder) -> Bool {
        return lhs.hash == rhs.hash
    }
}

class WeakDictionary<T1: AnyObject, T2> {
    private var dictionary = [WeakHolder<T1>: T2]()

    func set(forKey: T1, object: T2?) {
        dictionary[WeakHolder(object: forKey)] = object
    }

    func get(forKey: T1) -> T2? {
        let obj = dictionary[WeakHolder(object: forKey)]
        return obj
    }

    func forEach(_ handler: ((key: T1, value: T2)) -> Void) {
        dictionary.forEach {
            if let object = $0.key.object, let value = dictionary[$0.key] {
                handler((object, value))
            }
        }
    }
    
    func clean() {
        var removeList = [WeakHolder<T1>]()
        dictionary.forEach {
            if $0.key.object == nil {
                removeList.append($0.key)
            }
        }
        removeList.forEach {
            dictionary[$0] = nil
        }
    }
}
于 2020-11-12T12:34:01.337 回答
1

另一个使用Swift 3Swift 4的 Objective-C 关联对象和计算属性的例子

import CoreLocation

extension CLLocation {

    private struct AssociatedKeys {
        static var originAddress = "originAddress"
        static var destinationAddress = "destinationAddress"
    }

    var originAddress: String? {
        get {
            return objc_getAssociatedObject(self, &AssociatedKeys.originAddress) as? String
        }
        set {
            if let newValue = newValue {
                objc_setAssociatedObject(
                    self,
                    &AssociatedKeys.originAddress,
                    newValue as NSString?,
                    .OBJC_ASSOCIATION_RETAIN_NONATOMIC
                )
            }
        }
    }

    var destinationAddress: String? {
        get {
            return objc_getAssociatedObject(self, &AssociatedKeys.destinationAddress) as? String
        }
        set {
            if let newValue = newValue {
                objc_setAssociatedObject(
                    self,
                    &AssociatedKeys.destinationAddress,
                    newValue as NSString?,
                    .OBJC_ASSOCIATION_RETAIN_NONATOMIC
                )
            }
        }
    }

}
于 2017-08-21T13:32:16.877 回答
0

我尝试使用 objc_getAssociatedObject、objc_setAssociatedObject 来存储属性,但没有任何运气。我的目标是为 UITextField 创建扩展,以验证文本输入字符的长度。以下代码对我来说很好。希望这会对某人有所帮助。

private var _min: Int?
private var _max: Int?

extension UITextField {    
    @IBInspectable var minLength: Int {
        get {
            return _min ?? 0
        }
        set {
            _min = newValue
        }
    }

    @IBInspectable var maxLength: Int {
        get {
            return _max ?? 1000
        }
        set {
            _max = newValue
        }
    }

    func validation() -> (valid: Bool, error: String) {
        var valid: Bool = true
        var error: String = ""
        guard let text = self.text else { return (true, "") }

        if text.characters.count < minLength {
            valid = false
            error = "Textfield should contain at least \(minLength) characters"
        }

        if text.characters.count > maxLength {
            valid = false
            error = "Textfield should not contain more then \(maxLength) characters"
        }

        if (text.characters.count < minLength) && (text.characters.count > maxLength) {
            valid = false
            error = "Textfield should contain at least \(minLength) characters\n"
            error = "Textfield should not contain more then \(maxLength) characters"
        }

        return (valid, error)
    }
}
于 2016-12-02T09:27:43.190 回答
0

这是一个也有效的替代方案

public final class Storage : AnyObject {

    var object:Any?

    public init(_ object:Any) {
        self.object = object
    }
}

extension Date {

    private static let associationMap = NSMapTable<NSString, AnyObject>()
    private struct Keys {
        static var Locale:NSString = "locale"
    }

    public var locale:Locale? {
        get {

            if let storage = Date.associationMap.object(forKey: Keys.Locale) {
                return (storage as! Storage).object as? Locale
            }
            return nil
        }
        set {
            if newValue != nil {
                Date.associationMap.setObject(Storage(newValue), forKey: Keys.Locale)
            }
        }
    }
}



var date = Date()
date.locale = Locale(identifier: "pt_BR")
print( date.locale )
于 2017-06-23T18:06:51.457 回答
-2

我发现这个解决方案更实用

为 Swift 3 更新

extension UIColor {

    static let graySpace = UIColor.init(red: 50/255, green: 50/255, blue: 50/255, alpha: 1.0)
    static let redBlood = UIColor.init(red: 102/255, green: 0/255, blue: 0/255, alpha: 1.0)
    static let redOrange = UIColor.init(red: 204/255, green: 17/255, blue: 0/255, alpha: 1.0)

    func alpha(value : CGFloat) -> UIColor {
        var r = CGFloat(0), g = CGFloat(0), b = CGFloat(0), a = CGFloat(0)
        self.getRed(&r, green: &g, blue: &b, alpha: &a)
        return UIColor(red: r, green: g, blue: b, alpha: value)
    }

}

...然后在您的代码中

class gameController: UIViewController {

    @IBOutlet var game: gameClass!

    override func viewDidLoad() {
        self.view.backgroundColor = UIColor.graySpace

    }
}
于 2017-01-25T14:32:40.653 回答