0

我有一个带有事务注释的类：

@Service
@EnableTransactionManagement(order=2000)
public class UserManagementServiceImpl implements UserManagementService {
    @Transactional
    public User addUser(User user) throws AlreadyExistException {
        // ...
    }
}

我有一个方面类：

@Component
@Aspect
public class PublisherAspect {
    @Around("execution(* com.toi.expresso.service.UserManagementService.addUser(..))")
    public User publishAddUserEvent(ProceedingJoinPoint jp) {
        // ...
    }
}

在将数据保存在数据库中之前，我的@Around注释正在执行。addUser请建议我@Around将数据保存到数据库后如何执行。

4

2 回答 2

0

是 'adduser'返回用户对象。但是在持有用户对象之后，如果我正在检查同一用户的数据库，它返回的空集。

@Component
@Aspect
public class PublisherAspect {
    @Around("execution(User com.toi.expresso.service.UserManagementService.addUser(..))")
    public User publishAddUserEvent(ProceedingJoinPoint jp) 
       {
          // Do something before method execution
          User user = jp.proceed();
           //checking in database(Sending message to other application but that application didn't find user in same db)
            return user;
        }
    }
}
于 2014-08-21T04:38:59.177 回答
0

您方面的有趣部分是...，即建议体。假设您的addUser方法确实返回 aUser而不是void（我期望的）或其他任何内容，您可以将切入点缩小到实际具有User返回类型的方法，以避免返回其他类型的方法出现问题。

@Component
@Aspect
public class PublisherAspect {
    @Around("execution(User com.toi.expresso.service.UserManagementService.addUser(..))")
    public User publishAddUserEvent(ProceedingJoinPoint jp) {
        // Do something before method execution
        User user = jp.proceed();
        // Do something after method execution
        return user;
    }
}

如果要匹配所有返回类型，则更通用的解决方案：

@Component
@Aspect
public class PublisherAspect {
    @Around("execution(* com.toi.expresso.service.UserManagementService.addUser(..))")
    public Object publishAddUserEvent(ProceedingJoinPoint jp) {
        // Do something before method execution
        Object result = jp.proceed();
        // Do something after method execution
        return result;
    }
}
于 2014-08-20T16:09:27.880 回答