问题:在列中显示每个月在两个日期期间之间的周数(现在可以到三个月)。如果可能,从当天开始(动态)
我目前在哪里:
SELECT Q3.[Begin Date]
,Q3.[End Date]
,Q3.Diff_in_Year
,sum(CASE
WHEN Q3.Year_Counter = 0
THEN datediff(mm, Q3.y_start, Q3.y_end) + 1
ELSE 0
END) Y1
,sum(CASE
WHEN Q3.Year_Counter = 1
THEN datediff(mm, Q3.y_start, Q3.y_end) + 1
ELSE 0
END) Y2
,sum(CASE
WHEN Q3.Year_Counter = 2
THEN datediff(mm, Q3.y_start, Q3.y_end) + 1
ELSE 0
END) Y3
,sum(CASE
WHEN Q3.Year_Counter = 3
THEN datediff(mm, Q3.y_start, Q3.y_end) + 1
ELSE 0
END) Y4
,sum(CASE
WHEN Q3.Year_Counter = 4
THEN datediff(mm, Q3.y_start, Q3.y_end) + 1
ELSE 0
END) Y5
,sum(CASE
WHEN Q3.Year_Counter = 5
THEN datediff(mm, Q3.y_start, Q3.y_end) + 1
ELSE 0
END) Y6
,sum(CASE
WHEN Q3.Year_Counter = 6
THEN datediff(mm, Q3.y_start, Q3.y_end) + 1
ELSE 0
END) Y7
,sum(CASE
WHEN Q3.Year_Counter = 7
THEN datediff(mm, Q3.y_start, Q3.y_end) + 1
ELSE 0
END) Y8
,sum(CASE
WHEN Q3.Year_Counter = 8
THEN datediff(mm, Q3.y_start, Q3.y_end) + 1
ELSE 0
END) Y9
,sum(CASE
WHEN Q3.Year_Counter = 9
THEN datediff(mm, Q3.y_start, Q3.y_end) + 1
ELSE 0
END) Y10
FROM (
SELECT Q1.[Begin Date]
,Q1.[End Date]
,Q1.years Diff_in_Year
,Q2.number AS Year_Counter
,(
CASE
WHEN Q2.number = 0
THEN Q1.[Begin Date]
ELSE dateadd(yy, datediff(yy, 0, dateadd(yy, q2.number, q1.[Begin Date])), 0)
END
) AS y_Start
,(
CASE
WHEN ((Q1.years - 1) = Q2.number)
THEN Q1.[End Date]
ELSE DATEADD(yy, DATEDIFF(yy, 0, dateadd(yy, q2.number + 1, q1.[Begin Date]) + 1), - 1)
END
) AS y_End
,Year(Q1.[Begin Date]) + Q2.number YearInYYYY
FROM (
SELECT [Begin Date]
,[End Date]
,DATEDIFF(year, [Begin Date], [End Date]) + 1 AS years
FROM my dates
) Q1
INNER JOIN master..spt_values Q2 ON Q2.type = 'P'
AND Q2.number < Q1.years
) Q3
GROUP BY Q3.[Begin Date]
,Q3.[End Date]
,q3.Diff_in_Year
当前代码是如何工作的:给定一个日期范围,两个日期之间每年的月数。IE 1/1/2014 - 1/18/2015 将给出两列“2014”和 2015”,2014 的值为 12,2015 的值为 1,表示指定日期之间有 13 个月。
What I am hoping to achieve is something similar to
Start Date End Date Month 1 Month 2 Month 3
-----------------------------------------------------
1/1/2014 3/8/2014 4 4 1