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我有一些基本代码来加载一些精灵图像，我正在使用 Future.wait 等到两个图像都被加载。但是，这仍然不是我真正想要做的，因为我想在它退出之前将图像宽度和高度分配给成员。

SpaceShip(this.x, this.y) {
  rocket = new ImageElement(src: "nofire.png");
  firingRockets = new ImageElement(src: "fire.png");
  var futures = [rocket.onLoad.first, firingRockets.onLoad.first];
  Future.wait(futures).then((_) {
    width = rocket.width;
    height = rocket.height;
    print("Images loaded. $width $height");     
  });
  print("Returning");
}
....
ship = new SpaceShip(400.0, 200.0);
print("Ship Constructor exited");

输出：

Returning
Ship Constructor exited
Images loaded. 40 75

我想要一种方法等到所有图像加载完成后再退出构造函数。在 Dart 中有没有好的方法来做到这一点？

4

1 回答 1

1

我刚刚添加了一些评论为什么它不起作用

SpaceShip(this.x, this.y) {
  rocket = new ImageElement(src: "nofire.png");
  firingRockets = new ImageElement(src: "fire.png");
  var futures = [rocket.onLoad.first, firingRockets.onLoad.first];
  // this call just gets enqueued in the Dart event queue and then the 
  // execution is continued at the next statement
  // the async code is executed only after this thread of execution 
  // has ended
  Future.wait(futures).then((_) {
    width = rocket.width;
    height = rocket.height;
    print("Images loaded. $width $height");     
  });
  // this code doesn't wait for Future.wait to finish
  print("Returning");
}
....
// this code doesn't wait for Future.wait to finish
ship = new SpaceShip(400.0, 200.0);
print("Ship Constructor exited");

这样它应该可以工作（未经测试）

SpaceShip(this.x, this.y);

// I moved this to a method because the constructor can't return a Future
Future load() {
  rocket = new ImageElement(src: "nofire.png");
  firingRockets = new ImageElement(src: "fire.png");
  var futures = [rocket.onLoad.first, firingRockets.onLoad.first]; 
  return Future.wait(futures).then((_) {  // return a Future
    width = rocket.width;
    height = rocket.height;
    print("Images loaded. $width $height");     
  })
  .then(() {
    print("Returning");
  }});
}
....

var ship = new SpaceShip(400.0, 200.0);
// the returned future allows to wait until the async code has finished (using then)
ship.load().then(() {
    print("Ship Constructor exited");
});
于 2014-08-14T04:27:24.067 回答