编辑:虽然赞成,但这似乎不是正确的答案,对不起:
http://en.cppreference.com/w/cpp/memory/shared_ptr/operator_cmp
template< class T >
bool operator==( const shared_ptr<T>& lhs, std::nullptr_t rhs );
(7) (since C++11)
template< class T >
bool operator!=( const shared_ptr<T>& lhs, std::nullptr_t rhs );
(9) (since C++11)
7) !lhs
9) (bool)lhs
....破碎的实施?真的不知道。
使用 gcc -std=c++11 进行测试:(取自http://en.cppreference.com/w/cpp/memory/weak_ptr并改编)
#include <iostream>
#include <memory>
std::weak_ptr<int> gw;
void f()
{
auto spt = gw.lock();
if (spt != nullptr) {
std::cout << *spt << "\n";
}
else {
std::cout << "gw is expired\n";
}
}
int main()
{
{
auto sp = std::make_shared<int>(42);
gw = sp;
f();
}
f();
}
按预期输出:
42
gw过期了
必须在别处
原来的:
简而言之:将其检查为 bool,不要与 nullptr 进行比较(这将尝试lhs.get() == rhs.get()
在 nullptr 上使用 rhs = shared_ptr 失败):
auto foo_sharedptr = foo_weakptr.lock();
if (foo_sharedptr)
{
// do stuff with foo
}
请参阅文档:
#include <iostream>
#include <memory>
#include <thread>
void observe(std::weak_ptr<int> weak)
{
std::shared_ptr<int> observe(weak.lock());
if (observe) {
std::cout << "\tobserve() able to lock weak_ptr<>, value=" << *observe << "\n";
} else {
std::cout << "\tobserve() unable to lock weak_ptr<>\n";
}
}
int main()
{
std::weak_ptr<int> weak;
std::cout << "weak_ptr<> not yet initialized\n";
observe(weak);
{
std::shared_ptr<int> shared(new int(42));
weak = shared;
std::cout << "weak_ptr<> initialized with shared_ptr.\n";
observe(weak);
}
std::cout << "shared_ptr<> has been destructed due to scope exit.\n";
observe(weak);
}