0

我在 MySQL 数据库中有两个表。

  • 产品
  • order_item

客户下订单存储在表中的产品- 从到order_item的一对多关系。productorder_item

目前，我正在执行以下查询。

SELECT t0.prod_id, 
       sum(t1.quantity_ordered) 
FROM   projectdb.product t0, 
       projectdb.order_item t1 
WHERE  (t0.prod_id = t1.prod_id) 
GROUP  BY t0.prod_id 
HAVING (sum(t1.quantity_ordered) >= ?) 
ORDER  BY sum(t1.quantity_ordered) DESC

产生此 SQL 的条件查询如下。

CriteriaBuilder criteriaBuilder=entityManager.getCriteriaBuilder();
CriteriaQuery<Object[]>criteriaQuery=criteriaBuilder.createQuery(Object[].class);
Metamodel metamodel = entityManager.getMetamodel();
Root<OrderItem> root = criteriaQuery.from(metamodel.entity(OrderItem.class));

Join<OrderItem, Product> orderItemProdJoin = root.join(OrderItem_.prodId, JoinType.INNER);

List<Expression<?>>expressions=new ArrayList<Expression<?>>();
expressions.add(orderItemProdJoin.get(Product_.prodId));
expressions.add(criteriaBuilder.sum(root.get(OrderItem_.quantityOrdered)));
criteriaQuery.multiselect(expressions.toArray(new Expression[0]));

criteriaQuery.groupBy(orderItemProdJoin.get(Product_.prodId));
criteriaQuery.having(criteriaBuilder.greaterThanOrEqualTo(criteriaBuilder.sum(root.get(OrderItem_.quantityOrdered)), criteriaBuilder.literal(5)));

criteriaQuery.orderBy(criteriaBuilder.desc(criteriaBuilder.sum(root.get(OrderItem_.quantityOrdered))));
List<Object[]> list = entityManager.createQuery(criteriaQuery).getResultList();

此查询汇总表中每组产品的数量order_item。

它显示如下所示的行列表。

prod_id       qunatity_ordered

 6            11
 8             8
26             8
 7             7
31             7
12             6
27             6
24             5
 9             5

是否可以仅计算此查询产生的行数 - 在这种情况下为 9？

我在 EclipseLink 2.5.2 和 Hibernate 4.3.6 final 提供的 JPA 2.1 上。

4

2 回答 2

0

你有两个选择：

SELECT COUNT(*)
  FROM (
   SELECT 1, 
     FROM projectdb.product t0, 
          projectdb.order_item t1 
    WHERE (t0.prod_id = t1.prod_id) /* I prefer not to use Implicit Joins */
 GROUP BY t0.prod_id 
   HAVING (sum(t1.quantity_ordered) >= ?) 
       ) groups

或者：

list.size();
于 2014-08-13T10:49:12.670 回答
0

对此类行进行计数的一种方法是将给定查询包装在另一个对行进行计数的查询中，并使给定查询成为子查询，如下所示。

SELECT count(DISTINCT(t0.prod_id)) 
FROM   projectdb.product t0 
WHERE  EXISTS (SELECT t1.prod_id 
               FROM   projectdb.order_item t2, 
                      projectdb.product t1 
               WHERE  ((t1.prod_id = t0.prod_id ) 
                        AND ( t1.prod_id = t2.prod_id)) 
               GROUP  BY t1.prod_id 
               HAVING (sum(t2.quantity_ordered) >= ?))

产生上述 SQL 的条件查询。

CriteriaBuilder criteriaBuilder=entityManager.getCriteriaBuilder();
CriteriaQuery<Long>criteriaQuery=criteriaBuilder.createQuery(Long.class);
Metamodel metamodel = entityManager.getMetamodel();
Root<Product> root = criteriaQuery.from(metamodel.entity(Product.class));
criteriaQuery.select(criteriaBuilder.countDistinct(root));

Subquery<Long> orderItemSubquery = criteriaQuery.subquery(Long.class);
Root<OrderItem> orderItemRoot = orderItemSubquery.from(metamodel.entity(OrderItem.class));
Join<OrderItem, Product> orderItemProdJoin = orderItemRoot.join(OrderItem_.prodId, JoinType.INNER);

orderItemSubquery.select(orderItemProdJoin.get(Product_.prodId));
orderItemSubquery.where(criteriaBuilder.equal(root, orderItemRoot.get(OrderItem_.prodId)));
orderItemSubquery.groupBy(orderItemProdJoin.get(Product_.prodId));
orderItemSubquery.having(criteriaBuilder.greaterThanOrEqualTo(criteriaBuilder.sum(orderItemRoot.get(OrderItem_.quantityOrdered)), criteriaBuilder.literal(5)));
criteriaQuery.where(criteriaBuilder.exists(orderItemSubquery));

Long count = entityManager.createQuery(criteriaQuery).getSingleResult();
System.out.println("count = "+count);

我通常避免使用IN()子查询并使用EXISTS()子查询。尽管如此，可以使用IN()如下方式重写相同的查询。

SELECT count(DISTINCT(t0.prod_id)) 
FROM   projectdb.product t0 
WHERE  t0.prod_id IN (SELECT t1.prod_id 
                      FROM   projectdb.order_item t2, 
                             projectdb.product t1 
                      WHERE  (t1.prod_id = t2.prod_id) 
                      GROUP  BY t1.prod_id 
                      HAVING (sum(t2.quantity_ordered) >= ?))

对应的条件查询。

CriteriaBuilder criteriaBuilder=entityManager.getCriteriaBuilder();
CriteriaQuery<Long>criteriaQuery=criteriaBuilder.createQuery(Long.class);
Metamodel metamodel = entityManager.getMetamodel();
Root<Product> root = criteriaQuery.from(metamodel.entity(Product.class));
criteriaQuery.select(criteriaBuilder.countDistinct(root));

Subquery<Long> orderItemSubquery = criteriaQuery.subquery(Long.class);
Root<OrderItem> orderItemRoot = orderItemSubquery.from(metamodel.entity(OrderItem.class));
Join<OrderItem, Product> orderItemProdJoin = orderItemRoot.join(OrderItem_.prodId, JoinType.INNER);

orderItemSubquery.select(orderItemProdJoin.get(Product_.prodId));
orderItemSubquery.groupBy(orderItemProdJoin.get(Product_.prodId));
orderItemSubquery.having(criteriaBuilder.greaterThanOrEqualTo(criteriaBuilder.sum(orderItemRoot.get(OrderItem_.quantityOrdered)), criteriaBuilder.literal(5)));
criteriaQuery.where(criteriaBuilder.in(root.get(Product_.prodId)).value(orderItemSubquery));

Long count = entityManager.createQuery(criteriaQuery).getSingleResult();
System.out.println("count = "+count);

关于 ORM 的限制，我找不到比这更好的选择。

于 2014-08-13T16:38:43.177 回答