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我有以下代码制作活动工作簿的副本并为每个副本赋予不同的名称。它运作良好，但我真的需要运行代码的原始工作表才能保持活动状态。

如果我改用该SaveCopyAs函数，则复制的文件没有正确的文件格式（.xlsm），并且您不能像在saveAs函数中那样将文件格式指定为参数。

http://msdn.microsoft.com/en-us/library/bb178003%28v=office.12%29.aspx

http://msdn.microsoft.com/en-us/library/office/ff841185%28v=office.15%29.aspx

    Sub makeCopies()
        Dim name As Range, team As Range
        Dim uName As String, fName As String, fFormat As String
        Dim location as string, nName as string

        location ="c:\test\"
        nName = "Test - Team "
        Set team = Names("Team").RefersToRange

        For Each name In team
            uName = nName & name.Value
            fName = location & uName
            fFormat = ThisWorkbook.FileFormat
            ActiveWorkbook.SaveAs FileName:=fName, FileFormat:=fFormat
        Next name
   End sub

我能想到的最好的方法是首先制作副本，saveCopyAs然后访问每个文件，将其保存为正确的文件格式，saveAs然后关闭它，但这意味着双重工作，我真的很讨厌这样做。有没有更聪明的方法？

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1 回答 1

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这对我有用。SaveCopyAs以完全相同的格式保存工作簿。

Sub makeCopies()
    Dim name As Range, team As Range
    Dim uName As String, fName As String, tempname As String
    Dim location As String, nName As String

    location = "C:\Test\"
    nName = "Test - Team "
    Set team = ThisWorkbook.Names("Team").RefersToRange

    For Each name In team
        uName = nName & name.Value
        fName = location & uName & "." & _
            Split(ThisWorkbook.FullName, ".") _
            (UBound(Split(ThisWorkbook.FullName, ".")))
        ThisWorkbook.SaveCopyAs fName
    Next name
End Sub

这是你正在尝试的吗？尝试和测试。

于 2014-08-09T00:59:54.390 回答