6

有人知道如何检查有效的 IMEI 吗?

我在这个页面上找到了一个检查功能:http: //www.dotnetfunda.com/articles/article597-imeivalidator-in-vbnet-.aspx

但它会返回false有效的 IMEI (fe 352972024585360)。我可以在此页面上在线验证它们: http://www.numberingplans.com/?page=analysis& sub=imeinr

检查给定 IMEI 是否有效的正确方法(在 VB.Net 中)是什么?

PS:上面页面的这个功能一定是不正确的:

Public Shared Function isImeiValid(ByVal IMEI As String) As Boolean
    Dim cnt As Integer = 0
    Dim nw As String = String.Empty
    Try
        For Each c As Char In IMEI
            cnt += 1
            If cnt Mod 2 <> 0 Then
                nw += c
            Else
                Dim d As Integer = Integer.Parse(c) * 2 ' Every Second Digit has to be Doubled '
                nw += d.ToString() ' Genegrated a new number with doubled digits '
            End If
        Next
        Dim tot As Integer = 0
        For Each ch As Char In nw.Remove(nw.Length - 1, 1)
            tot += Integer.Parse(ch) ' Adding all digits together '
        Next
        Dim chDigit As Integer = 10 - (tot Mod 10) ' Finding the Check Digit my Finding the Remainder of the sum and subtracting it from 10 '
        If chDigit = Integer.Parse(IMEI(IMEI.Length - 1)) Then ' Checking the Check Digit with the last digit of the Given IMEI code '
            Return True
        Else
            Return False
        End If
    Catch ex As Exception
        Return False
    End Try
End Function

编辑:这是我的工作“checkIMEI”-功能:

Public Shared Function checkIMEI(ByRef IMEI As String) As Boolean
    Const allowed As String = "0123456789"

    Dim cleanNumber As New System.Text.StringBuilder
    For i As Int32 = 0 To IMEI.Length - 1
        If (allowed.IndexOf(IMEI.Substring(i, 1)) >= 0) Then
            cleanNumber.Append(IMEI.Substring(i, 1))
        End If
    Next

    If cleanNumber.Length <> 15 Then
        Return False
    Else
        IMEI = cleanNumber.ToString
    End If

    For i As Int32 = cleanNumber.Length + 1 To 16
        cleanNumber.Insert(0, "0")
    Next

    Dim multiplier As Int32, digit As Int32, sum As Int32, total As Int32 = 0
    Dim number As String = cleanNumber.ToString()

    For i As Int32 = 1 To 16
        multiplier = 1 + (i Mod 2)
        digit = Int32.Parse(number.Substring(i - 1, 1))
        sum = digit * multiplier
        If (sum > 9) Then
            sum -= 9
        End If
        total += sum
    Next

    Return (total Mod 10 = 0)
End Function
4

2 回答 2

11

IMEI 号码使用Luhn算法进行验证。链接页面具有各种语言的实现。这篇文章还有一些更多的实现和关于如何解决 Luhn 算法的一般方法。

于 2010-03-25T15:02:02.933 回答
1

IMEISV(IMEI 软件版本)没有 Luhn 算法校验位。相反,它的软件版本号显示为两位数。IMEI 号码的格式多年来一直在发展。

我认为维基百科是一个很好的来源,可以看到格式多年来的变化。如果您查看新的 IMEI 和 IMEISV 版本格式,您会看到最终组装代码 (FAC) 已删除,类型分配代码 (TAC) 增加了 8 位。互联网上有免费和商业的 TAC 列表。

通过在 Luhn 算法验证新旧 IMEI 号码之上查找 TAC 列表来验证 TAC 号码可能是一个选项。对于旧的 IMEI 号码,FAC 作为 2 位数字应被丢弃,TAC 验证应针对 6 位数字进行。

于 2018-12-31T12:03:09.313 回答