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我正在尝试使用数据库将 ExtJs 连接到 PHP，并且无法向网格面板显示数据，我很困惑为什么网格面板中没有数据显示并且萤火虫中没有错误。任何人都可以检查并纠正我或教如何使用 PHP 创建一个简单的网格面板。我正在使用 Extjs 5

//应用商店/

Ext.define('TestPhp.store.Employee', {
      extend: 'Ext.data.JsonStore',
      alias: 'store.employees',
      model: 'TestPhp.model.Employ',
    proxy: {
        type: 'ajax',
        url: 'test.php',
        reader: {
            type: 'json',
            rootPropety: 'data'
        }
    },   });

//应用程序/模型/

Ext.define('TestPhp.model.Employ', {
     extend: 'Ext.data.Model',
    fields: ['name','bounty','power'],    
});

//应用程序/视图/主/

 Ext.define('TestPhp.view.main.Grid', {
    extend: 'Ext.Panel',
    xtype: 'gridp',

require:['TestPhp.store.Employee'],

    store: 'Employee',
 items:[{
            style: 'padding-top: 10px;',
            xtype: 'grid',
            style: 'margin-top:5px;margin-left:10px;',
            columns : [

                {
                text     : 'Name',
                width    : '40%',
                sortable : false,
                dataIndex: 'name'
            },
            {
                text     : 'Bounty',
                width    : '30%',
                sortable : true,
                dataIndex: 'bounty'
            },
            {
                text     : 'Power',
                width    : '30%',
                sortable : true,
                dataIndex: 'power'
            }

            ],

            width: '100%'
        }],
  });

//我的php文件

<?php

 mysql_connect("localhost", "root", "") or
  die("Could not connect: " . mysql_error());
  mysql_select_db("test_db");

$query= "SELECT * FROM pirate";
$result= mysql_query($query);

    $return_arr= array();

    while($rows = mysql_fetch_array($result, MYSQL_ASSOC)){
            // $row_array['id']=$rows['id'];
            $row_array['name']=$rows['name'];
            $row_array['bounty']=$rows['bounty'];
            $row_array['power']=$rows['power'];

            array_push($return_arr, $row_array);
}

$ans = array('success' => true, );
$ans['data'] = $return_arr;
header('Content-Type: application/json');
print json_encode($ans);
exit;

?>

这是php文件的输出.....

{"success":true,"data":[{"name":"luffy","bounty":"400000000","power":"gum gum no mi and haki"},{"name":"zorro ","bounty":"300000000","power":"3剑式和霸气"},{"name":"sanji","bounty":"100000000","power":"黑脚式和霸气"},{"name":"Ace","bounty":"400000000","power":"flare flare no mi and haki"},{"name":"sabo","bounty":"40000000000" ,"power":"unknown"},{"name":"rayleigh","bounty":"unknown","power":"unknown"}]}

4

1 回答 1

1

埃文用代码回答：替换

extend: 'Ext.Panel',

经过

extend: 'Ext.grid.Panel',

然后，将 autoLoad: true 添加到商店或在创建网格之前加载商店。将此代码调整为您的用例：

this.getStore('Employee').load()
Ext.widget('gridp')
于 2014-08-06T04:50:31.680 回答