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我的教授给了我这段代码，我唯一要做的就是 TODO 区域。我对python还是很陌生，从来没有接触过这种类型的项目，所以我很困惑。这个项目的所有目的是获取绘制的图形图像。

import math, random, pylab
class Location(object):
    def __init__(self, x, y):
        self.x = float(x)
        self.y = float(y)
    def move(self, xc, yc):
        return Location(self.x+float(xc), self.y+float(yc))
    def getCoords(self):
        return self.x, self.y
    def getDist(self, other):
        ox, oy = other.getCoords()
        xDist = self.x - ox
        yDist = self.y - oy
        return math.sqrt(xDist**2 + yDist**2)
class CompassPt(object):
    possibles = ('N', 'S', 'E', 'W')
    def __init__(self, pt):
        if pt in self.possibles: self.pt = pt
        else: raise ValueError('in CompassPt.__init__')
    def move(self, dist):
        if self.pt == 'N': return (0, dist)
        elif self.pt == 'S': return (0, -dist)
        elif self.pt == 'E': return (dist, 0)
        elif self.pt == 'W': return (-dist, 0)
        else: raise ValueError('in CompassPt.move')
class Field(object):
    def __init__(self, drunk, loc):
        self.drunk = drunk
        self.loc = loc
    def move(self, cp, dist):
        oldLoc = self.loc
        xc, yc = cp.move(dist)
        self.loc = oldLoc.move(xc, yc)
    def getLoc(self):
        return self.loc
    def getDrunk(self):
        return self.drunk
class Drunk(object):
    def __init__(self, name):
        self.name = name
    def move(self, field, time = 1):
        if field.getDrunk() != self:
            raise ValueError('Drunk.move called with drunk not in field')
        for i in range(time):
            pt = CompassPt(random.choice(CompassPt.possibles))
            field.move(pt, 1)

这是我需要做并尝试做的部分。到目前为止，我的图表没有移动大声笑。我在图表中间得到一个点，除非它在可能的情况下随机走在一个位置，哈哈。

# TODO TODO TODO TODO TODO TODO TODO TODO TODO TODO TODO TODO
def performTrial(time, f):
    start = f.getLoc()
    # TODO
    distances = [0.0] 
    for t in range(1, time + 1):
        # TODO
        f.getDrunk().move(f) 
        newLoc = f.getLoc() 
        distance = newLoc.getDist(start) 
        distances.append(distance) 
    xcoords, ycoords = distances[::2], distances[1::2]
    return xcoords,ycoords
# END OF TODOEND OF TODO END OF TODO END OF TODO END OF TODO

这里的其余部分也是教授提供的

drunk = Drunk('Homer Simpson')
for i in range(1):
    f = Field(drunk, Location(0, 0))
    coords = performTrial(500, f)
    print(coords)
    pylab.plot(coords[0],coords[1],marker='^',linestyle=':',color='b')
pylab.title('Homer\'s Random Walk')
pylab.xlabel('Time')
pylab.ylabel('Distance from Origin')
pylab.show()

更新：修复了坐标，但现在我得到一个错误：

in _xy_from_xy(self, x, y)
    235         y = np.atleast_1d(y)
    236         if x.shape[0] != y.shape[0]:
--> 237             raise ValueError("x and y must have same first dimension")
    238         if x.ndim > 2 or y.ndim > 2:
    239             raise ValueError("x and y can be no greater than 2-D")

ValueError: x and y must have same first dimension
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1 回答 1

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def move(self, xc, yc):
    return Location(self.x+float(xc), self.y+float(yc))

这不会移动任何东西，它只是返回新的坐标。也不需要将 xc 和 yc 转换为浮点数。

如果此功能旨在移动位置，则必须添加：

def move(self, xc, yc):
    self.x += xc
    self.y += yc
    return Location(self.x, self.y)
于 2014-08-01T09:27:00.560 回答