21

我正在尝试生成一个 XML 文档,其中包含没有使用前缀的默认命名空间XmlSerializer,例如

<?xml version="1.0" encoding="utf-8" ?>
<MyRecord ID="9266" xmlns="http://www.website.com/MyRecord">
    <List>
        <SpecificItem>

使用以下代码...

string xmlizedString = null;
MemoryStream memoryStream = new MemoryStream();
XmlSerializer xs = new XmlSerializer(typeof(ExportMyRecord));
XmlSerializerNamespaces xmlnsEmpty = new XmlSerializerNamespaces();
xmlnsEmpty.Add(string.Empty, string.Empty);
XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.UTF8);
xs.Serialize(xmlTextWriter, myRecord, xmlnsEmpty);
memoryStream = (MemoryStream)xmlTextWriter.BaseStream;
xmlizedString = this.UTF8ByteArrayToString(memoryStream.ToArray());

和班级结构...

[Serializable]
[XmlRoot("MyRecord")]
public class ExportMyRecord
{
    [XmlAttribute("ID")]
    public int ID { get; set; }

现在,我尝试了各种选择...

XmlSerializer xs = new XmlSerializer
                     (typeof(ExportMyRecord),"http://www.website.com/MyRecord");

或者 ...

[XmlRoot(Namespace = "http://www.website.com/MyRecord", ElementName="MyRecord")]

给我 ...

<?xml version="1.0" encoding="utf-8"?>
<q1:MylRecord ID="9266" xmlns:q1="http://www.website.com/MyRecord">
    <q1:List>
        <q1:SpecificItem>

我需要 XML 具有不带前缀的命名空间,因为它会发送给第三方提供商,并且他们拒绝所有其他替代方案。

4

2 回答 2

40

你去:

ExportMyRecord instance = GetInstanceToSerializeFromSomewhere();
XmlSerializerNamespaces xmlnsEmpty = new XmlSerializerNamespaces();
xmlnsEmpty.Add(string.Empty, "http://www.website.com/MyRecord");
var serializer = new XmlSerializer(
    instance.GetType(), 
    "http://www.website.com/MyRecord"
);
于 2010-03-26T09:09:08.180 回答
1

这是一个可用于任何类型的通用实现:

public static void Serialize<T>(T instance, string defaultNamespace, Stream stream)
{
    var namespaces = new XmlSerializerNamespaces();
    namespaces.Add(string.Empty, defaultNamespace);
    var serializer = new XmlSerializer(typeof(T), defaultNamespace);
    serializer.Serialize(stream, instance, namespaces);
}
于 2019-01-31T15:01:42.190 回答