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出于调试目的，我想访问具有特定属性集的不同子例程的词法范围。这很好用。当第一个变量存储一个字符串时出现问题，然后我得到一个空字符串。我做这样的事情：

$pad = $cv->PADLIST; # $cv is the coderef to the sub
@scatchpad = $pad->ARRAY; # getting the scratchpad
@varnames = $scratchpad[0]->ARRAY; # getting the variablenames
@varcontents = $scratchpad[1]->ARRAY; # getting the Content from the vars

for (0 .. $#varnames) {
    eval {
        my $name = $varnames[$_]->PV;
        my $content;
        # following line  matches numbers, works so far
        $content = $varcontent[$_]->IVX if (scalar($varcontent[$_]) =~ /PVIV=/);
        # should match strings, but does give me undef
        $content = B::perlstring($varcontent[$_]->PV) if (scalar($varcontent[$_]) =~ /PV=/);
        print "DEBUGGER> Local variable: ", $name, " = ", $content, "\n";
    }; # there are Special vars that throw a error, but i don't care about them
}

就像我在评论中所说的那样，评估是为了防止暂存器中 B::Special 对象的错误。输出：

Local variable: $test = 42
Local variable: $text = 0

第一个输出没问题，第二个应该输出“TEXT”而不是0。

我究竟做错了什么？

编辑：通过一点编码，我得到了变量的所有值，但没有存储在@varnames 和@varcontents 的相同索引中。所以现在的问题是如何（以何种顺序）将值存储在@varcontents 中。

use strict;
use warnings;
use B;

sub testsub {
    my $testvar1 = 42;
    my $testvar2 = 21;
    my $testvar3 = "testval3";
    print "printtest1";
    my $testvar4 = "testval4";
    print "printtest2";
    return "returnval";
}

no warnings "uninitialized";

my $coderef = \&testsub;
my $cv = B::svref_2object ( $coderef );
my $pad = $cv->PADLIST; # get scratchpad object
my @scratchpad = $pad->ARRAY;
my @varnames = $scratchpad[0]->ARRAY; # get varnames out of scratchpad
my @varcontents = $scratchpad[1]->ARRAY; # get content array out of scratchpad

my @vars; # array to store variable names adn "undef" for special objects (print-values, return-values, etc.)

for (0 .. $#varnames) {
    eval { push @vars, $varnames[$_]->PV; };
    if ($@) { push @vars, "undef"; }
}

my @cont; # array to store the content of the variables and special objects

for (0 .. $#varcontents) {
    eval { push @cont, $varcontents[$_]->IV; };
    eval { push @cont, $varcontents[$_]->PV; };
}

print $vars[$_], "\t\t\t", $cont[$_], "\n" for (0 .. $#cont);

EDIT2：添加了可运行脚本来演示该问题：变量名和变量值未存储在两个数组（@varnames 和 @varcontents）的同一索引中。

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