是否有任何实用程序（或示例源代码）可以在 Java 中截断 HTML（用于预览）？我想在服务器上而不是在客户端上进行截断。
我正在使用 HTMLUnit 来解析 HTML。
更新：
我希望能够预览 HTML，因此截断器将保持 HTML 结构，同时在所需的输出长度之后剥离元素。
问问题
2171 次
6 回答
4
我编写了另一个 java 版本的 truncateHTML。此函数将字符串截断为多个字符，同时保留整个单词和 HTML 标记。
public static String truncateHTML(String text, int length, String suffix) {
// if the plain text is shorter than the maximum length, return the whole text
if (text.replaceAll("<.*?>", "").length() <= length) {
return text;
}
String result = "";
boolean trimmed = false;
if (suffix == null) {
suffix = "...";
}
/*
* This pattern creates tokens, where each line starts with the tag.
* For example, "One, <b>Two</b>, Three" produces the following:
* One,
* <b>Two
* </b>, Three
*/
Pattern tagPattern = Pattern.compile("(<.+?>)?([^<>]*)");
/*
* Checks for an empty tag, for example img, br, etc.
*/
Pattern emptyTagPattern = Pattern.compile("^<\\s*(img|br|input|hr|area|base|basefont|col|frame|isindex|link|meta|param).*>$");
/*
* Modified the pattern to also include H1-H6 tags
* Checks for closing tags, allowing leading and ending space inside the brackets
*/
Pattern closingTagPattern = Pattern.compile("^<\\s*/\\s*([a-zA-Z]+[1-6]?)\\s*>$");
/*
* Modified the pattern to also include H1-H6 tags
* Checks for opening tags, allowing leading and ending space inside the brackets
*/
Pattern openingTagPattern = Pattern.compile("^<\\s*([a-zA-Z]+[1-6]?).*?>$");
/*
* Find > ...
*/
Pattern entityPattern = Pattern.compile("(&[0-9a-z]{2,8};|&#[0-9]{1,7};|[0-9a-f]{1,6};)");
// splits all html-tags to scanable lines
Matcher tagMatcher = tagPattern.matcher(text);
int numTags = tagMatcher.groupCount();
int totalLength = suffix.length();
List<String> openTags = new ArrayList<String>();
boolean proposingChop = false;
while (tagMatcher.find()) {
String tagText = tagMatcher.group(1);
String plainText = tagMatcher.group(2);
if (proposingChop &&
tagText != null && tagText.length() != 0 &&
plainText != null && plainText.length() != 0) {
trimmed = true;
break;
}
// if there is any html-tag in this line, handle it and add it (uncounted) to the output
if (tagText != null && tagText.length() > 0) {
boolean foundMatch = false;
// if it's an "empty element" with or without xhtml-conform closing slash
Matcher matcher = emptyTagPattern.matcher(tagText);
if (matcher.find()) {
foundMatch = true;
// do nothing
}
// closing tag?
if (!foundMatch) {
matcher = closingTagPattern.matcher(tagText);
if (matcher.find()) {
foundMatch = true;
// delete tag from openTags list
String tagName = matcher.group(1);
openTags.remove(tagName.toLowerCase());
}
}
// opening tag?
if (!foundMatch) {
matcher = openingTagPattern.matcher(tagText);
if (matcher.find()) {
// add tag to the beginning of openTags list
String tagName = matcher.group(1);
openTags.add(0, tagName.toLowerCase());
}
}
// add html-tag to result
result += tagText;
}
// calculate the length of the plain text part of the line; handle entities (e.g. ) as one character
int contentLength = plainText.replaceAll("&[0-9a-z]{2,8};|&#[0-9]{1,7};|[0-9a-f]{1,6};", " ").length();
if (totalLength + contentLength > length) {
// the number of characters which are left
int numCharsRemaining = length - totalLength;
int entitiesLength = 0;
Matcher entityMatcher = entityPattern.matcher(plainText);
while (entityMatcher.find()) {
String entity = entityMatcher.group(1);
if (numCharsRemaining > 0) {
numCharsRemaining--;
entitiesLength += entity.length();
} else {
// no more characters left
break;
}
}
// keep us from chopping words in half
int proposedChopPosition = numCharsRemaining + entitiesLength;
int endOfWordPosition = plainText.indexOf(" ", proposedChopPosition-1);
if (endOfWordPosition == -1) {
endOfWordPosition = plainText.length();
}
int endOfWordOffset = endOfWordPosition - proposedChopPosition;
if (endOfWordOffset > 6) { // chop the word if it's extra long
endOfWordOffset = 0;
}
proposedChopPosition = numCharsRemaining + entitiesLength + endOfWordOffset;
if (plainText.length() >= proposedChopPosition) {
result += plainText.substring(0, proposedChopPosition);
proposingChop = true;
if (proposedChopPosition < plainText.length()) {
trimmed = true;
break; // maximum length is reached, so get off the loop
}
} else {
result += plainText;
}
} else {
result += plainText;
totalLength += contentLength;
}
// if the maximum length is reached, get off the loop
if(totalLength >= length) {
trimmed = true;
break;
}
}
for (String openTag : openTags) {
result += "</" + openTag + ">";
}
if (trimmed) {
result += suffix;
}
return result;
}
于 2011-12-06T21:57:56.473 回答
1
这里有一个 PHP 函数：http: //snippets.dzone.com/posts/show/7125
我已经为初始版本制作了一个快速而肮脏的 Java 端口，但是评论中有后续改进的版本可能值得考虑（尤其是处理整个单词的版本）：
public static String truncateHtml(String s, int l) {
Pattern p = Pattern.compile("<[^>]+>([^<]*)");
int i = 0;
List<String> tags = new ArrayList<String>();
Matcher m = p.matcher(s);
while(m.find()) {
if (m.start(0) - i >= l) {
break;
}
String t = StringUtils.split(m.group(0), " \t\n\r\0\u000B>")[0].substring(1);
if (t.charAt(0) != '/') {
tags.add(t);
} else if ( tags.get(tags.size()-1).equals(t.substring(1))) {
tags.remove(tags.size()-1);
}
i += m.start(1) - m.start(0);
}
Collections.reverse(tags);
return s.substring(0, Math.min(s.length(), l+i))
+ ((tags.size() > 0) ? "</"+StringUtils.join(tags, "></")+">" : "")
+ ((s.length() > l) ? "\u2026" : "");
}
注意：您需要 Apache Commons Lang 用于StringUtils.join().
于 2011-06-09T08:01:08.647 回答
0
我可以为您提供我为此编写的 Python 脚本：http ://www.ellipsix.net/ext-tmp/summarize.txt 。不幸的是，我没有 Java 版本，但如果您愿意，可以自己翻译并修改它以满足您的需要。它不是很复杂，只是我为我的网站一起破解的东西，但我已经使用了一年多一点，而且它通常看起来工作得很好。
如果您想要一些健壮的东西，那么 XML（或 SGML）解析器几乎肯定是比我所做的更好的主意。
于 2010-03-24T02:24:47.797 回答
0
我发现了这个博客： dencat：在 Java 中截断 HTML
它包含一个 Python 的 java 端口，Django 模板函数truncate_html_words
于 2013-01-03T16:24:04.327 回答
0
public class SimpleHtmlTruncator {
public static String truncateHtmlWords(String text, int max_length) {
String input = text.trim();
if (max_length > input.length()) {
return input;
}
if (max_length < 0) {
return new String();
}
StringBuilder output = new StringBuilder();
/**
* Pattern pattern_opentag = Pattern.compile("(<[^/].*?[^/]>).*");
* Pattern pattern_closetag = Pattern.compile("(</.*?[^/]>).*"); Pattern
* pattern_selfclosetag = Pattern.compile("(<.*?/>).*");*
*/
String HTML_TAG_PATTERN = "<(\"[^\"]*\"|'[^']*'|[^'\">])*>";
Pattern pattern_overall = Pattern.compile(HTML_TAG_PATTERN + "|" + "\\s*\\w*\\s*");
Pattern pattern_html = Pattern.compile("(" + HTML_TAG_PATTERN + ")" + ".*");
Pattern pattern_words = Pattern.compile("(\\s*\\w*\\s*).*");
int characters = 0;
Matcher all = pattern_overall.matcher(input);
while (all.find()) {
String matched = all.group();
Matcher html_matcher = pattern_html.matcher(matched);
Matcher word_matcher = pattern_words.matcher(matched);
if (html_matcher.matches()) {
output.append(html_matcher.group());
} else if (word_matcher.matches()) {
if (characters < max_length) {
String word = word_matcher.group();
if (characters + word.length() < max_length) {
output.append(word);
} else {
output.append(word.substring(0,
(max_length - characters) > word.length()
? word.length() : (max_length - characters)));
}
characters += word.length();
}
}
}
return output.toString();
}
public static void main(String[] args) {
String text = SimpleHtmlTruncator.truncateHtmlWords("<html><body><br/><p>abc</p><p>defghij</p><p>ghi</p></body></html>", 4);
System.out.println(text);
}
}
于 2014-09-09T09:08:14.633 回答