0

我有这个代码：

declare
  instr varchar2(20);
  num_no number;

begin 
    select AR_ID, ID
    into instr, num_no
    from quelle_match
    where ID = 1;

      execute immediate 'CREATE or replace VIEW interm2 AS
      SELECT AR_ID, kurs,
        ((TO_CHAR(to_date(di.kursdatum,''dd.mm.yyyy''),''YYYYMMDD''))+    (TO_CHAR(to_date(di.verfall,''dd.mm.yyyy''),''YYYYMMDD''))) AS dumdate
      FROM daten_import di 
      where di.AR_ID = '||instr||'';      

  -- where di.AR_ID = ''GXIndex''';

end ;

我收到错误 b/c instr is not valid。当我用实际的字符串 GXIndex 替换变量时，代码可以工作。它也适用于数字作为变量，但不适用于字符串。这是为什么？

4

2 回答 2

1

这个：

  execute immediate 'CREATE or replace VIEW interm2 AS
  SELECT AR_ID, kurs,
    ((TO_CHAR(to_date(di.kursdatum,''dd.mm.yyyy''),''YYYYMMDD''))+    (TO_CHAR(to_date(di.verfall,''dd.mm.yyyy''),''YYYYMMDD''))) AS dumdate
  FROM daten_import di 
  where di.AR_ID = '||instr||'';

应该：

  execute immediate 'CREATE or replace VIEW interm2 AS
  SELECT AR_ID, kurs,
    ((TO_CHAR(to_date(di.kursdatum,''dd.mm.yyyy''),''YYYYMMDD''))+    (TO_CHAR(to_date(di.verfall,''dd.mm.yyyy''),''YYYYMMDD''))) AS dumdate
  FROM daten_import di 
  where di.AR_ID = '||instr;

ifinstr是一个整数，我认为是。

于 2014-07-25T19:05:04.020 回答
0

你的连接方式有问题instr。为清楚起见，让我简化您的问题：

EXECUTE IMMEDIATE
  'CREATE OR REPLACE VIEW interm2 AS
   SELECT ar_id FROM daten_import di
   WHERE di.ar_id = ' || instr;

instr是一个字符串。你需要在它周围加上引号。

EXECUTE IMMEDIATE
  'CREATE OR REPLACE VIEW interm2 AS
   SELECT ar_id FROM daten_import di
   WHERE di.ar_id = ''' || instr || '''';
--                  ^^               ^^
--                  ||               ||
--                  -- escaped quotes--
于 2014-08-25T23:49:37.720 回答