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我正在使用 XSLT 处理 IDML 文件。在从 InDesign 导出的 IDML 中，它同时运行相同样式的连续段落，由<Br/>标签分隔，如下所示（我的输入 XML）：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Story>
    <ParagraphStyleRange AppliedParagraphStyle="ParagraphStyle/para">
        <CharacterStyleRange AppliedCharacterStyle="CharacterStyle/$ID/[No character style]">
            <Content>All rights reserved. No part of this publication may be reproduced in any material form (including photocopying or storing it in any medium by electronic means and whether or not transiently or incidentally to some other use of this publication) without the written permission of the copyright owner except in accordance with the provisions of the Copyright, Designs and Patents Act 1988 or under the terms of a licence issued by the </Content>
        </CharacterStyleRange>
        <CharacterStyleRange AppliedCharacterStyle="CharacterStyle/italic">
            <Content>Copyright Licensing Agency Ltd, Saffron House, 6-10 Kirby Street, London, EC1N 8TS England</Content>
        </CharacterStyleRange>
        <CharacterStyleRange AppliedCharacterStyle="CharacterStyle/$ID/[No character style]">
            <Content>. Applications for the copyright owner’s written permission to reproduce any part of this publication should be addressed to the publisher.</Content>
            <Br/>
            <Content>Warning: The doing of an unauthorised act in relation to a copyright work may result in both a civil claim for damages and criminal prosecution.</Content>
            <Br/>
            <Content>Crown copyright material is reproduced with the permission of the Controller of HMSO and the Queen’s Printer for Scotland.</Content>
            <Br/>
        </CharacterStyleRange>
    </ParagraphStyleRange>
</Story>

现在，我需要将其转换为如下所示的 XML

<?xml version="1.0" encoding="UTF-8"?>
<story> 
    <para>All rights reserved. No part of this publication may be reproduced in any material form (including photocopying or storing it in any medium by electronic means and whether or not transiently or incidentally to some other use of this publication) without the written permission of the copyright owner except in accordance with the provisions of the Copyright, Designs and Patents Act 1988 or under the terms of a licence issued by the <italic>Copyright Licensing Agency Ltd, Saffron House, 6-10 Kirby Street, London, EC1N 8TS England</italic>. Applications for the copyright owner’s written permission to reproduce any part of this publication should be addressed to the publisher.</para>
    <para>Warning: The doing of an unauthorised act in relation to a copyright work may result in both a civil claim for damages and criminal prosecution.</para>
    <para>Crown copyright material is reproduced with the permission of the Controller of HMSO and the Queen’s Printer for Scotland.</para>
</story>

我的 XSL 看起来像这样：

<?xml version="1.0" ?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:template match="/Story">
        <story>
            <xsl:apply-templates/>
        </story>
    </xsl:template>

    <xsl:template match="ParagraphStyleRange">
        <xsl:apply-templates>
            <xsl:with-param name="para_style_name" select="replace(./@AppliedParagraphStyle, 'ParagraphStyle/', '')"/>
        </xsl:apply-templates>
    </xsl:template>

    <xsl:template match="CharacterStyleRange">
        <xsl:param name="para_style_name"/>
        <xsl:variable name="char_style_name" select="replace(./@AppliedCharacterStyle, 'CharacterStyle/', '')"/>
        <xsl:for-each-group select="*" group-ending-with="Br">
            <xsl:element name="{$para_style_name}">
                <xsl:choose>
                    <xsl:when test="$char_style_name = '$ID/[No character style]'">
                        <xsl:apply-templates select="current-group()"/>
                    </xsl:when>
                    <xsl:otherwise>
                        <xsl:element name="{$char_style_name}">
                            <xsl:apply-templates select="current-group()"/>
                        </xsl:element>
                    </xsl:otherwise>
                </xsl:choose>
            </xsl:element>
        </xsl:for-each-group>
    </xsl:template>

    <xsl:template match="Content">
        <xsl:value-of select="."/>
    </xsl:template>

    <xsl:template match="Br"/>

</xsl:stylesheet>

这几乎可以工作，除了第一个para在italic部分分开。

<?xml version="1.0" encoding="UTF-8"?>
<story> 
    <para>All rights reserved. No part of this publication may be reproduced in any material form (including photocopying or storing it in any medium by electronic means and whether or not transiently or incidentally to some other use of this publication) without the written permission of the copyright owner except in accordance with the provisions of the Copyright, Designs and Patents Act 1988 or under the terms of a licence issued by the </para>
    <para><italic>Copyright Licensing Agency Ltd, Saffron House, 6-10 Kirby Street, London, EC1N 8TS England</italic></para>
    <para>. Applications for the copyright owner’s written permission to reproduce any part of this publication should be addressed to the publisher.</para>
    <para>Warning: The doing of an unauthorised act in relation to a copyright work may result in both a civil claim for damages and criminal prosecution.</para>
    <para>Crown copyright material is reproduced with the permission of the Controller of HMSO and the Queen’s Printer for Scotland.</para>
</story>

CharacterStyleRange正如预期的那样，我的分组方法在跨越输入中的多个元素时不起作用。但是有没有一种可以工作的分组方法？还是我最好采取不同的方法，例如终止CharacterStyleRange并ParagraphStyleRange在每个Br地方重新打开它们作为简化处理的中间步骤？

4

1 回答 1

0

所以，你快到了。将分组向上移动一级并在匹配 ParagraphStyleRange 的模板中进行：

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="2.0">

<xsl:output indent="yes"/>

<xsl:template match="Story">
    <story>
        <xsl:apply-templates select="ParagraphStyleRange"/>
    </story>
</xsl:template>

<xsl:template match="ParagraphStyleRange">
    <xsl:variable name="para_style_name" select="replace(@AppliedParagraphStyle, 'ParagraphStyle/', '')"/>
    <xsl:for-each-group select="CharacterStyleRange/*" group-ending-with="Br">
        <xs:element name="{para_style_name}">
            <xsl:apply-templates select="current-group()[self::Content]"/>
        </xs:element>
    </xsl:for-each-group>
</xsl:template>

<xsl:template match="Content">
    <xsl:variable name="char_style_name" select="replace(../@AppliedCharacterStyle, 'CharacterStyle/', '')"/>
    <xsl:choose>
        <xsl:when test="$char_style_name = '$ID/[No character style]'">
            <xsl:value-of select="."/>
        </xsl:when>
        <xsl:otherwise>
            <xsl:element name="{$char_style_name}">
                <xsl:value-of select="."/>
            </xsl:element>
        </xsl:otherwise>
    </xsl:choose>
</xsl:template>

</xsl:stylesheet>
于 2014-07-24T12:19:08.950 回答