sql - 如何使用 SQL Server 2008 将学生分数分组为五分位数

Question

谁能帮我把学生的分数分成五分之一？我认为 SQL Server 2012 中有一个功能，但我们仍然有t upgraded to it as we are using 2008R2. I triedNtile(5)`，但它没有产生所需的结果。我需要在 Quintile 列下方

Student   Score Quintile
------------------------    
Student1     20   1
Student2     20   1
Student3     30   2
Student4     30   2
Student5     40   2
Student6     40   2
Student7     50   3
Student8     50   3
Student9     60   3
Student10    70   4
Student11    70   4
Student12    80   4
Student13    80   4
Student14    90   5

Answer 1

使用时您一定做错了什么NTILE(5)-这就是要使用的功能！

这是我的测试设置：

DECLARE @Students TABLE (StudentID INT IDENTITY(1,1), StudentName VARCHAR(20), Score INT)

INSERT INTO @Students(StudentName, Score)
VALUES ('Student 1', 20), ('Student 2', 20), 
('Student 3', 30), ('Student 4', 30), 
('Student 5', 40), ('Student 6', 40), 
('Student 7', 50), ('Student 8', 50), 
('Student 9', 60), 
('Student 10', 70), ('Student 11', 70), 
('Student 12', 80), ('Student 13', 80), 
('Student 14', 90)


SELECT 
    StudentName, Score, 
    Quintile = NTILE(5) OVER(ORDER BY Score)
FROM    
    @Students

输出是：

Answer 2

借自 marc_s +1

DECLARE @Students TABLE (StudentID INT IDENTITY(1,1), StudentName VARCHAR(20), Score INT)

INSERT INTO @Students(StudentName, Score)
VALUES ('Student 1', 20), ('Student 2', 20), 
('Student 3', 30), ('Student 4', 30), 
('Student 5', 40), ('Student 6', 40), 
('Student 7', 50), ('Student 8', 50), 
('Student 9', 60), ('Student 10', 70), 
('Student 11', 70),('Student 12', 80), 
('Student 13', 80),('Student 14', 90)

SELECT s.StudentName, s.Score, qm.maxQ
  FROM @Students as s
  join ( select score, MAX(Quintile) as maxQ
           from ( SELECT Score, Quintile = NTILE(5) OVER(ORDER BY Score)
                    FROM  @Students ) q 
          group by q.score ) qm
    on qm.Score = s.Score

Answer 3

Below is the correct answer given by Erland Sommarskog 
Create Table #Scores(Student varchar(20), Score int); 
Insert #Scores(Student, Score) Values 
('Student1', 20) 
,('Student2', 20) 
,('Student3', 30)
,('Student4', 30)
,('Student4', 30)
,('Student4', 30)
,('Student5', 40)
,('Student6', 40)
,('Student7', 50)
,('Student8', 50)
,('Student9', 60)
,('Student10', 70)
,('Student11', 70) 
,('Student12', 80) 
,('Student13', 80) 
,('Student14', 90); 

; WITH quintiles AS (
    SELECT Score, ntile(5) OVER(ORDER BY Score) AS quintile 
    FROM   (SELECT DISTINCT Score FROM #Scores) AS s 
)
SELECT s.Student, s.Score, q.quintile
FROM   #Scores s
JOIN   quintiles q ON s.Score = q.Score
go
DROP TABLE #Scores

--by Erland Sommarskog``