0

我有两个模型用户和员工需要相互交互。这是一个基于示例应用程序（控制器）的控制器。我需要它对这两种模型都有效，但为 def 添加一个 if/else 语句，例如邮箱等，以确定员工或用户是否登录显示“堆栈级别太深”错误。我是 Rails 新手，在多次谷歌搜索/SO 之后无法理解我的错误是什么。消息传递应该在这两个模型之间，发起者应该是用户。（更新：我发现Mailboxer Gem--Restrict 消息传递的 SO 帖子）非常感谢！

class ConversationsController < ApplicationController
  before_filter :authenticate_employee! or authenticate_user!
  helper_method :mailbox, :conversation

  def create
    recipient_emails = conversation_params(:recipients).split(',')
    recipients = User.where(email: recipient_emails).all
if(user_signed_in?)
    conversation = current_user.send_message(recipients, *conversation_params(:body, :subject)).conversation
else
  conversation = current_employee.send_message(recipients, *conversation_params(:body, :subject)).conversation
end
    redirect_to conversation_path(conversation)

end

  def reply
    current_user.reply_to_conversation(conversation, *message_params(:body, :subject))
    redirect_to conversation_path(conversation)
  end

  def trash
    conversation.move_to_trash(current_user)
    redirect_to :conversations
  end

  def untrash
    conversation.untrash(current_user)
    redirect_to :conversations
  end

  private

  def mailbox
    if(user_signed_in?)
    @mailbox ||= current_user.mailbox
else
    @mailbox ||= current_employee.mailbox
end
    redirect_to conversation_path(conversation)  
end


  def conversation
    @conversation ||= mailbox.conversations.find(params[:id])
  end

  def conversation_params(*keys)
    fetch_params(:conversation, *keys)
  end

  def message_params(*keys)
    fetch_params(:message, *keys)
  end

  def fetch_params(key, *subkeys)
    params[key].instance_eval do
      case subkeys.size
      when 0 then self
      when 1 then self[subkeys.first]
      else subkeys.map{|k| self[k] }
      end
    end
  end
end`
4

1 回答 1

0

“堆栈级别太深”错误通常是由于无限循环/递归/重定向而出现的。查看您上面的代码，我没有看到任何明显的罪魁祸首，但使用 pry 进行调试可能会帮助您追踪它。

于 2014-07-22T03:56:03.380 回答