bash - How to avoid such code duplications in a Bash script?

Question

In one of my Bash scripts I have such code repeated twice:

    find "$source_dir" -type f \
            -iname "*.arw" \
            -or -iname "*.cr2" \
            -or -iname "*.crw" \
            -or -iname "*.jpeg" \
            -or -iname "*.jpg" \
            -or -iname "*.nef" \
            -or -iname "*.nrw" \
            -or -iname "*.orf" \
            -or -iname "*.pef" \
            -or -iname "*.png" \
            -or -iname "*.ptx" \
            -or -iname "*.raf" \
            -or -iname "*.raw" \
            -or -iname "*.rw2" \
            -or -iname "*.sr2" \
            -or -iname "*.srf" \
            -or -iname "*.srw" \
            -or -iname "*.tif" \
            -or -iname "*.tiff" \
            -or -iname "*.x3f" | (

     counter=0

     while read image_file; do
            (...)

There are two such find commands both performed on different directories, but with exactly the same parameters. Results of each finds are processed in a different ways. I am convinced that it is possible to avoid code duplication here. Is there a way to wrap this find command into a function that stores find results in some data structure? Such data structure must be passed to the subshell that iterates over its items. How can I achieve this?

Answer 1

将 find 命令包装为函数

function myfind() {
   find ....
}

然后像使用新命令一样使用它

myfind | while read image_file; do ....