有没有人认为以下有什么问题:
$.ajax({
url: '/tags/ajax/post-tag/',
data: { newtaginput : $('#tag-input').val(), customerid : $('#customerid').val()},
success: function(data) {
// After posting
alert(data);
arr = data.tagsinserted.split(',');
alert(arr);
//Loop through
$.each(arr, function(n, val){
alert(n + ' ' + val)
});
}
}, "json");
tagsinserted 是返回的内容,这是完整的响应:
{"returnmessage":"The Ajax operation was successful.","tagsinserted":"b7,b4,dog,cat","returncode":"0"}
谢谢