10

我有一个 JSON 文档，看起来像：

{ "series": [[1,2], [2,3], [3,4]] }

我想将其解析为一组数据类型：

data Series = Series [DataPoint]
data DataPoint = DataPoint Int Int  -- x and y

我在尝试FromJSON为 DataPoint 编写实例时遇到了很多问题。

instance FromJSON DataPoint where
  parseJSON (Array a) = ???

我尝试使用 Lens 来破坏 DataPoint 记录，但它无法编译：

case a ^.. values . _Integer of -}
  [x,y] -> DataPoint <$> x <*> y
  _     -> mzero

这个错误失败了（前两行我什至没有镜头技巧，只是试图创建一个DataPoint <$> 1 <*> 2）：

Couldn't match type ‘aeson-0.7.0.6:Data.Aeson.Types.Internal.Parser
                       Integer’
              with ‘Integer’
Expected type: (aeson-0.7.0.6:Data.Aeson.Types.Internal.Parser
                  Integer
                -> Const
                     (Data.Monoid.Endo
                        [aeson-0.7.0.6:Data.Aeson.Types.Internal.Parse
                     (aeson-0.7.0.6:Data.Aeson.Types.Internal.Parser I
               -> Value
               -> Const
                    (Data.Monoid.Endo
                       [aeson-0.7.0.6:Data.Aeson.Types.Internal.Parser
                    Value
  Actual type: (Integer
                -> Const
                     (Data.Monoid.Endo
                        [aeson-0.7.0.6:Data.Aeson.Types.Internal.Parse
                     Integer)
               -> Value
               -> Const
                    (Data.Monoid.Endo
                       [aeson-0.7.0.6:Data.Aeson.Types.Internal.Parser
                    Value
In the second argument of ‘(.)’, namely ‘_Integer’
In the second argument of ‘(^..)’, namely ‘values . _Integer’

有一个更好的方法吗？

有人有将值数组解析为更详细结构的示例吗？

4

2 回答 2

16

Aeson 有列表的实例，所以我认为没有必要处理向量。

{-# LANGUAGE LambdaCase #-}
import Data.Aeson

data Series = Series [DataPoint]
data DataPoint = DataPoint Int Int

instance FromJSON DataPoint where
  parseJSON jsn = do
    [x,y] <- parseJSON jsn
    return $ DataPoint x y

instance FromJSON Series where
  parseJSON = \case
    Object o -> (o .: "series") >>= fmap Series . parseJSON
    x -> fail $ "unexpected json: " ++ show x
于 2014-07-14T18:33:30.933 回答
4

The trick here is getting the instance for FromJSON DataPoint correct, which takes a little bit of matching but isn't too bad. I came up with

instance FromJSON DataPoint where
    parseJSON (Array v)
        | V.length v == 2 = do
            x <- parseJSON $ v V.! 0
            y <- parseJSON $ v V.! 1
            return $ DataPoint x y
        | otherwise = mzero
    parseJSON _ = mzero

Which will fail to parse cleanly if it isn't able to pull two Ints out for x and y. Then you just have to define the instance for Series:

instance FromJSON Series where
    parseJSON (Object o) = do
        pts <- o .: "series"
        ptsList <- mapM parseJSON $ V.toList pts
        return $ Series ptsList
    parseJSON _ = mzero

Which, again, will cleanly fail if the data is malformed anywhere. To test:

> decode "{\"series\": [[1, 2], [3, 4]]}" :: Maybe Series
Just (Series [DataPoint 1 2, DataPoint 3 4])
> decode "{\"series\": [[1, 2], [3, {}]]}" :: Maybe Series
Nothing

So it looks like it works.

EDIT: As @maxtaldykin has pointed out, you can just take advantage of the FromJSON a => FromJSON [a] instance with

instance FromJSON DataPoint where
    parseJSON obj = do
        [x, y] <- parseJSON obj
        return $ DataPoint x y

instance FromJSON Series where
    parseJSON (Object o) = do
        pts <- o .: "series"
        fmap Series $ parseJSON pts
    parseJSON _ = mzero

Which is greatly simplified from my original answer. Kudos to Max.

于 2014-07-14T18:27:39.683 回答