7

我有一个这样定义的模型

class Lga < ActiveRecord::Base
  validates_uniqueness_of :code
  validates_presence_of :name
end

我已经为 Lgas 定义了一个工厂

Factory.sequence(:lga_id) { |n| n + 10000 }

Factory.define :lga do |l|
  id = Factory.next :lga_id
  l.code "lga_#{id}"
  l.name "LGA #{id}"
end

但是，当我跑步时

Factory.create(:lga)
Factory.create(:lga)

在script/console我得到

>> Factory.create(:lga)
=> #<Lga id: 2, code: "lga_10001", name: "LGA 10001", created_at: "2010-03-18  23:55:29", updated_at: "2010-03-18 23:55:29">
>> Factory.create(:lga)
ActiveRecord::RecordInvalid: Validation failed: Code has already been taken
4

2 回答 2

7

问题在于code，name属性并不是所谓的惰性属性。我曾想过写一些类似的东西：

Factory.define :lga do |l|
  l.code { |n| "lga_#{n+10000}" }
end

但我也想重用name属性中的 id 。您可以通过将其放入挂钩来确保id每次Factory.create调用都对其进行评估。after_build

Factory.define :lga do |l|
   l.after_build do |lga|
     id = Factory.next :lga_id
     lga.code = "lga_#{id}"
     lga.name = "LGA #{id}"
   end
end

这仅适用于 FactoryGirl 1.2.3 及更高版本。

于 2010-03-19T00:03:53.760 回答
2

之前的答案仍然正确，但在较新版本的 FactoryGirl 中，您会收到警告。

Factory.next has been depreciated. Use FactoryGirl.generate instead.

新代码应如下所示：

Factory.define :lga do |l|
   l.after_build do |lga|
     id = FactoryGirl.generate :lga_id
     lga.code = "lga_#{id}"
     lga.name = "LGA #{id}"
   end
end

资料来源： http: //notesofgreg.blogspot.co.uk/2012/07/foolproof-factorygirl-sequence.html

于 2012-07-10T13:19:22.840 回答