1

我这里有个小问题..

for(int i=0; i<employee.length-1;i++){

            if(employee[i].getID()==ID){
                System.out.println("Employee Record for "+employee[i].getfName()+" "+employee[i].getlName()+" (ID#"+employee[i].getID()+"):\n"
                        + "Basic Pay: "+employee[i].getSalary(0)+"\n"
                        + "Housing Allowence: "+employee[i].getSalary(1)+"\n"
                        + "Travel Allowence:  "+employee[i].getSalary(2)+"\n"
                        + "Net Salary : "+employee[i].getNetSalary()+"\n"
                        + "Taxable : "+employee[i].getTaxable());break;}


       if(i==employee.length-1){
           System.out.println("EMPLOYEE NOT FOUND !!!");}

这是我通过 id 搜索员工的代码。我在运行时收到一条错误消息！这些值是由用户输入的，我对此没有问题

错误信息：

Exception in thread "main" java.lang.NullPointerException
    at dd1318398p2.EmpRecord.searchEmpID(EmpRecord.java:103)
    at dd1318398p2.EmpRecord.main(EmpRecord.java:37)
Java Result: 1

错误是指第一个 if 语句

4

1 回答 1

2

如果错误是指第一if条语句，

if(employee[i].getID()==ID)

这给了你一个 NullPointerException 然后employee[i]必须为空。你可以检查一下，

if (employee[i] != null && employee[i].getID()==ID)

或者，如果您需要一堆 if 测试，请使用 continue...

if (employee[i] == null) continue;
if(employee[i].getID()==ID) {
}
于 2014-07-13T23:40:30.117 回答