python - 如何比较熊猫的频率/采样率？

Question

有没有办法说 '13Min' 是 > '59S' 和 <'2H' 使用熊猫中的频率符号？

Answer 1

In [4]: from pandas.tseries.frequencies import to_offset

In [5]: to_offset('59s') < to_offset('1T')
Out[5]: True

In [6]: to_offset('13T') > to_offset('59s')
Out[6]: True

In [7]: to_offset('13T') < to_offset('59s')
Out[7]: False

In [8]: to_offset('13T') > to_offset('2H')
Out[8]: False

In [10]: to_offset('13T') < to_offset('2H')
Out[10]: True

Answer 2

另一种方法是将两个频率添加到一个公共日期并比较Timestamp. 这也解决了@rixmit的评论。

In [2]: import pandas as pd
In [3]: from pandas.tseries.frequencies import to_offset

In [4]: common_dt = pd.to_datetime("2000-01-01")
In [5]: f_a = common_dt + to_offset('59s')
In [6]: f_b = common_dt + to_offset('1T')
In [7]: f_a > f_b
Out[8]: False

In [9]: f_a = common_dt + to_offset('M')
In [9]: f_b = common_dt + to_offset('W')
In [10]: f_a > f_b
Out[10]: True