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我想在同一个 SELECT mdx 语句中添加一个具有不同维度的度量。一般来说，我的大部分措施都与[客户创建日期].[日期层次结构].[月份名称]相关联。但是，匿名客户没有客户创建日期的链接；因此，我必须将匿名链接到查询创建日期。如何将两个度量组合到单个选择查询中。

> WITH  MEMBER [Measures].[Allow Contact] as
            ([Measures].[# CRM Customers],[Customer].[Customer Allow Contact].&[Yes],[Customer].[Customer Status].&[Active] )

        MEMBER [Measures].[Total Identified Customers] AS
            ([Measures].[# CRM Customers],[Customer].[Customer Status].&[Active] )

        MEMBER [Measures].[Anonymous Customers] AS
            ([Measures].[# Unique Distinct Customers on Contact],[Enquiry].[Anonymous].&[Yes]) 



SELECT NON EMPTY {  Measures].[Allow Contact], 
                    [Measures].[Total Identified Customers]
                    //,[Measures].[Anonymous Customers]

                 } ON COLUMNS
       ,NON EMPTY ([Customer Creation Date].[Date Hierarchy].[Month Name]
       //,[Enquiry Creation Date].[Date Hierarchy].[Month Name] //How to add different dimensionality  

       ) ON ROWS
FROM [Cube]
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1 回答 1

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如果两个时间维度具有相同的结构（如果它们被实现为同一维度对象上的角色扮演维度，显然应该是这种情况），您可以使用定义中的LinkMember函数[Measures].[Anonymous Customers]来使用[Customer Creation Date].[Date Hierarchy]行中的 ，但使用这些日期如[Enquiry Creation Date].[Date Hierarchy]在度量计算中：

WITH  MEMBER [Measures].[Allow Contact] as
            ([Measures].[# CRM Customers],[Customer].[Customer Allow Contact].&[Yes],[Customer].[Customer Status].&[Active] )

        MEMBER [Measures].[Total Identified Customers] AS
            ([Measures].[# CRM Customers],[Customer].[Customer Status].&[Active] )

        MEMBER [Measures].[Anonymous Customers] AS
            ([Measures].[# Unique Distinct Customers on Contact],[Enquiry].[Anonymous].&[Yes], 
             LinkMember([Customer Creation Date].[Date Hierarchy].CurrentMember, [Enquiry Creation Date].[Date Hierarchy]) 

SELECT NON EMPTY {  Measures].[Allow Contact], 
                    [Measures].[Total Identified Customers]
                   ,[Measures].[Anonymous Customers]
                 } ON COLUMNS
       ,NON EMPTY ([Customer Creation Date].[Date Hierarchy].[Month Name]
       ) ON ROWS
FROM [Cube]
于 2014-07-08T16:52:39.327 回答