我目前正在使用以下 PHP 代码:
// Get all subordinates
$subords = array();
$supervisorID = $this->session->userdata('supervisor_id');
$result = $this->db->query(sprintf("SELECT * FROM users WHERE supervisor_id=%d AND id!=%d",$supervisorID, $supervisorID));
$user_list_query = 'user_id='.$supervisorID;
foreach($result->result() as $user){
$user_list_query .= ' OR user_id='.$user->id;
$subords[$user->id] = $user;
}
// Get Submissions
$submissionsResult = $this->db->query(sprintf("SELECT * FROM submissions WHERE %s", $user_list_query));
$submissions = array();
foreach($submissionsResult->result() as $submission){
$entriesResult = $this->db->query(sprintf("SELECT * FROM submittedentries WHERE timestamp=%d", $submission->timestamp));
$entries = array();
foreach($entriesResult->result() as $entries) $entries[] = $entry;
$submissions[] = array(
'user' => $subords[$submission->user_id],
'entries' => $entries
);
$entriesResult->free_result();
}
基本上,我得到了一个用户列表,这些用户是给定 supervisor_id 的下属(每个用户条目都有一个 supervisor_id 字段),然后抓取属于这些用户中的任何一个的条目。
我不禁想到有一种更优雅的方式来做到这一点,比如SELECT FROM tablename where user->supervisor_id=2222
PHP/MySQL 有类似的东西吗?
可能应该在某个时候正确地学习关系数据库。:(
编辑:这是相关的架构
submissions
===============================
id, user_id, timestamp
submittedentries
===============================
id, user_id, timestamp
users
===============================
id, supervisor_id, email
一个submission
有很多submittedentries
,目前我正在使用时间戳来引用它。如果有人可以提出更有效的方法,我非常愿意改变这一点。(是的,我省略了更多字段)