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我正在尝试遍历返回的 JSON 对象并根据 x 和 y 坐标绘制热图。这是我设置热图的方法:

function getHeatMap() {
heatLayer = new HeatmapLayer({
    config: {
        "useLocalMaximum": true,
        "radius": 40,
        "gradient": {
            0.45: "rgb(000,000,255)",
            0.55: "rgb(000,255,255)",
            0.65: "rgb(000,255,000)",
            0.95: "rgb(255,255,000)",
            1.00: "rgb(255,000,000)"
        }
    },
    "map": map,
    "domNodeId": "heatLayer",
    "opacity": 0.85
});

$.ajax({
    url: "index.aspx/getBusCommuter",
    type: "POST",
    data: "",
    contentType: "application/json; charset=utf-8",
    dataType: "json",
    success: function (data) {
        var parsed = JSON.parse(data.d);
        var data = [];
        $.each(parsed, function (i, jsondata) {
            var coordXicon = jsondata.BusStopX;
            var coordYicon = jsondata.BusStopY;

            data = [
                {
                    attributes: {},
                    geometry: {
                        spatialReference: { wkid: 102100 },
                        type: "point",
                        x: coordXicon,
                        y: coordYicon
                    }
                }
           ];
        });
        heatLayer.setData(data);
        map.addLayer(heatLayer);
    },
    error: function (request, state, errors) {
    }
});

}

基本上,JSON 对象只会循环到最后一组 JSON 对象并仅绘制最后一组而不是全部。我想知道我的逻辑的哪一部分是错误的。

提前致谢。

4

1 回答 1

1

问题在这里:

data = [
    {
        attributes: {},
        geometry: {
            spatialReference: {
                wkid: 102100
            },
            type: "point",
            x: coordXicon,
            y: coordYicon
        }
    }
];

当您可能只想将新元素推到末尾时,您正在为每个项目设置整个数据数组(覆盖所有旧数据)。试试这个:

data.push({ ... });
于 2014-07-04T05:59:03.323 回答