0
foreach($response_2['items'] as $item) {
$item['track']['name'] = (array)$item['track']['name'];
foreach($item['track']['name'] as $key => $value) {
    echo $value . "<br />";
}
$item['track']['artists']['name'] = (array)$item['track']['artists']['name'];
foreach($item['track']['artists']['name'] as $key => $value) {
    echo $value . "<br />";
} 
$item['track']['duration_ms'] = (array)$item['track']['duration_ms'];
foreach($item['track']['duration_ms'] as $key => $value) {
    echo $value . "<br />";
    } 
}

...解析此响应: http: //pastebin.com/uxBF3Kxe#(在我解码后)。

['track']['name']和的所有值['track']['duration_ms']都正确回显,但没有回显['track']['artists']['name']

我在这里做错了什么?

谢谢!

4

1 回答 1

1

['track']['artists']是数组:)

尝试这个 ;)

foreach($item['track']['artists'] as $key => $value) {
    echo $value['name'] . "<br />";
}

顺便说一句...这是更好的解决方案;)

$response_2 = json_decode($json, true);

foreach($response_2['items'] as $item) {
    echo $item['track']['name'] . "<br />";

    foreach($item['track']['artists'] as $key => $value) {
        echo $value['name'] . "<br />";
    }

    echo $item['track']['duration_ms'] . "<br />";
}

/ ** 添加分隔符* /

$response_2 = json_decode($json, true);

foreach($response_2['items'] as $item) {
    echo $item['track']['name'] . "<br />";

    echo implode(',', array_map(
            function ($value) {
                return $value['name'];
            },
            $item['track']['artists']
        )
    );

    echo "<br />";

    echo $item['track']['duration_ms'] . "<br />";
}
于 2014-07-03T11:23:29.520 回答