346

我有一个在 MySQL 中运行良好的查询，但是当我在 Oracle 上运行它时出现以下错误：

SQL 错误：ORA-00933：SQL 命令未正确结束
00933。00000 -“SQL 命令未正确结束”

查询是：

UPDATE table1
INNER JOIN table2 ON table1.value = table2.DESC
SET table1.value = table2.CODE
WHERE table1.UPDATETYPE='blah';
4

15 回答 15

476

该语法在 Oracle 中无效。你可以这样做：

UPDATE table1 SET table1.value = (SELECT table2.CODE
                                  FROM table2 
                                  WHERE table1.value = table2.DESC)
WHERE table1.UPDATETYPE='blah'
AND EXISTS (SELECT table2.CODE
            FROM table2 
            WHERE table1.value = table2.DESC);

或者你可以这样做：

UPDATE 
(SELECT table1.value as OLD, table2.CODE as NEW
 FROM table1
 INNER JOIN table2
 ON table1.value = table2.DESC
 WHERE table1.UPDATETYPE='blah'
) t
SET t.OLD = t.NEW

这取决于 Oracle 是否认为内联视图可更新（第二条语句的可更新取决于 此处列出的一些规则）。

于 2010-03-15T11:53:02.883 回答
226

用这个：

MERGE
INTO    table1 trg
USING   (
        SELECT  t1.rowid AS rid, t2.code
        FROM    table1 t1
        JOIN    table2 t2
        ON      table1.value = table2.DESC
        WHERE   table1.UPDATETYPE='blah'
        ) src
ON      (trg.rowid = src.rid)
WHEN MATCHED THEN UPDATE
    SET trg.value = code;
于 2010-03-15T11:58:30.100 回答
35

MERGE带WHERE子句：

MERGE into table1
USING table2
ON (table1.id = table2.id)
WHEN MATCHED THEN UPDATE SET table1.startdate = table2.start_date
WHERE table1.startdate > table2.start_date;

You need the WHERE clause because columns referenced in the ON clause cannot be updated.

于 2015-05-07T14:12:15.490 回答
15

Do not use some of the answers above.

Some suggest the use of nested SELECT, don't do that, it is excruciatingly slow. If you have lots of records to update, use join, so something like:

update (select bonus 
        from employee_bonus b 
        inner join employees e on b.employee_id = e.employee_id 
        where e.bonus_eligible = 'N') t
set t.bonus = 0;

See this link for more details. http://geekswithblogs.net/WillSmith/archive/2008/06/18/oracle-update-with-join-again.aspx.

Also, ensure that there are primary keys on all the tables you are joining.

于 2017-04-04T22:36:54.363 回答
14 
 UPDATE ( SELECT t1.value, t2.CODE
          FROM table1 t1
          INNER JOIN table2 t2 ON t1.Value = t2.DESC
          WHERE t1.UPDATETYPE='blah')
 SET t1.Value= t2.CODE
于 2010-03-15T11:58:12.410 回答
7

As indicated here, the general syntax for the first solution proposed by Tony Andrews is :

update some_table s
set   (s.col1, s.col2) = (select x.col1, x.col2
                          from   other_table x
                          where  x.key_value = s.key_value
                         )
where exists             (select 1
                          from   other_table x
                          where  x.key_value = s.key_value
                         )

I think this is interesting especially if you want update more than one field.

于 2016-01-14T12:37:44.580 回答
3

以下语法对我有用。

UPDATE
(SELECT A.utl_id,
    b.utl1_id
    FROM trb_pi_joint A
    JOIN trb_tpr B
    ON A.tp_id=B.tp_id Where A.pij_type=2 and a.utl_id is null
)
SET utl_id=utl1_id;
于 2013-01-24T05:18:48.960 回答
3

It works fine oracle

merge into table1 t1
using (select * from table2) t2
on (t1.empid = t2.empid)
when matched then update set t1.salary = t2.salary
于 2015-09-04T04:40:53.577 回答
1

对 table2使用描述而不是 desc，

update
  table1
set
  value = (select code from table2 where description = table1.value)
where
  exists (select 1 from table2 where description = table1.value)
  and
  table1.updatetype = 'blah'
;
于 2010-03-15T12:04:07.750 回答
1 
UPDATE table1 t1
SET t1.value = 
    (select t2.CODE from table2 t2 
     where t1.value = t2.DESC) 
WHERE t1.UPDATETYPE='blah';
于 2014-06-05T07:59:54.907 回答
1 
UPDATE (SELECT T.FIELD A, S.FIELD B
FROM TABLE_T T INNER JOIN TABLE_S S
ON T.ID = S.ID)
SET B = A;

A and B are alias fields, you do not need to point the table.

于 2017-05-30T09:47:58.800 回答
0 
UPDATE IP_ADMISSION_REQUEST ip1
SET IP1.WRIST_BAND_PRINT_STATUS=0
WHERE IP1.IP_ADM_REQ_ID        =
  (SELECT IP.IP_ADM_REQ_ID
  FROM IP_ADMISSION_REQUEST ip
  INNER JOIN VISIT v
  ON ip.ip_visit_id=v.visit_id
  AND v.pat_id     =3702
  ); `enter code here`
于 2015-12-16T09:53:24.270 回答
0

Just as a matter of completeness, and because we're talking Oracle, this could do it as well:

declare
begin
  for sel in (
    select table2.code, table2.desc
    from table1
    join table2 on table1.value = table2.desc
    where table1.updatetype = 'blah'
  ) loop
    update table1 
    set table1.value = sel.code
    where table1.updatetype = 'blah' and table1.value = sel.desc;    
  end loop;
end;
/
于 2019-02-19T08:58:50.130 回答
0

Oracle base has a good run down on this.

https://oracle-base.com/articles/misc/updates-based-on-queries

From this link - I used a modification of the above query which did not work for me (the answer from mathguy which uses rowid)

MERGE /*+ APPEND PARALLEL(8) */ INTO dest_table tt
USING source_table st
ON (tt.identifier = st.identifier)
WHEN MATCHED THEN
  UPDATE SET tt.number = st.number;

Here I have two tables: source and dest. They both have a varchar field in common and I am adding the source identify field (PK) into the dest table.

于 2020-11-09T13:51:43.313 回答
-3 
update table1  a 
   set a.col1='Y' 
 where exists(select 1 
                from table2 b
               where a.col1=b.col1 
                 and a.col2=b.col2
             )
于 2015-11-27T15:58:43.010 回答