android - Loopj AsynHttpClient 发布请求响应

Question

Loopj AsynHttpClient

ASP.NET

我正在尝试连接到 ASP.NET WebApp。
OnSuccess 回调，我想读取网页并从网页中获取文本和数据。我怎样才能得到它，或者我怎样才能将它解析为 JSON 或 XML？我通过将参数发布到登录页面成功连接到该站点。现在我想阅读重定向的网页。以及如何保存 cookie 或缓存，以便在我运行 Android APP 时自动登录。

client.get("https://uogis.uog.edu.pk/LandingPage.aspx", new AsyncHttpResponseHandler(){

                @Override
                public void onFailure(int arg0, Header[] arg1,
                        byte[] arg2, Throwable arg3) {
                    // TODO Auto-generated method stub

                }

                @Override
                public void onSuccess(int arg0, Header[] arg1,
                        byte[] arg2) {
                    // TODO Auto-generated method stub
                    mTextView.setText("In Landing Page now");

                }
                @Override
                public void onFinish() {
                    params.put("TextBox1","Home");
                    client.get("https://uogis.uog.edu.pk/ControlPanel.aspx",new AsyncHttpResponseHandler(){

                        @Override
                        public void onFailure(int arg0,
                                Header[] arg1, byte[] arg2,
                                Throwable arg3) {
                            // TODO Auto-generated method stub

                        }

                        @Override
                        public void onSuccess(int arg0,
                                Header[] arg1, byte[] arg2) {
                            // TODO Auto-generated method stub

                            mTextView.setText("In Control Panel\n"+ "ResponseCode "+arg0+ "\n" );
                        }});

                }
            });